No. Without friction or air resistance, no force is required to keep an object moving
at a constant velocity.
Also, by the way, just thought we should mention: In deep space, the ship has no weight.
If we start from newtons third law, we can get the idea of action and reaction is equal and opposite It is its' fuel ejection that enables the rocket to fly forward. P=MV But here mass is decreasing due to the consumption of fuel thus, we are now flying at P= (M-m)V WHERE M grater than (M-m) hence the rocket clearly is moving at a constantly decreasing mass with constant velocity. therefore it clearly accelerates as time goes. Samuel
positive acceleration
Assuming constant acceleration, at a higher speed, the force must be applied over a larger distance to get the same change in speed. Since work = force x distance, it requires more work to get the same change in speed, once the rocket has a higher speed.In the case of the rocket, the situation is not as simple as you put it. For example, all the fuel the rocket required to change the rocket's speed, say, from 1000 m/s to 1100 m/s, must be accelerated first, using more fuel at first. Also, the exhaust gases from the rocket have kinetic energy, which depend on the rocket's current speed - when it is just starting, the exhaust gases have a higher speed, and therefore more kinetic energy. To see whether energy is conserved or not, this kinetic energy would have to be included in your calculations.
It may unless it has an attached parachute
Thrust on the rocket depends only on the engines. It doesn't matter whether the rocket is sitting on the pad or out somewhere a million miles from nowhere.
the initial velocity of the rocket is zero.
it is just like gravitational effect on a rocket it is the max vel required to overcome the circular motion tangential to the centripetal force
No.Orbital Velocity is the velocity required by a body to achieve a circular orbit around its primary.Escape velocity is the minimum velocity needed to escape a gravitational field
The stages of a rocket going into space: The first stage of a rocket is used to acquire the acceleration of a rocket. When the fuel of the first stage is exhausted ,it detaches from the rockets and drops off. The velocity at this stage becomes the initial velocity of the second stage .Now the second stage is ignited ,the rocket gains acceleration and it's velocity foes on increasing . The removal of the surplus mass contained in the first stage helps in attaining the higher velocity .When the fuel of the second stage is exhausted ,it too detached from the rocket .Finally at the third stage , the rocket starts off with the required velocity.
Assuming its engines are off, it would travel at a constant speed ONLY if there is no force of gravity that changes its velocity. In practice, there are always forces that will change its velocity, at least in the long term.
Effective jet velocity of a rocket is the increased velocity of a rocket in a short span of time. It is achieved with the use of either solid or liquid propellants.Ê
the rocket speed required to escape out of the earth's gravity is known as escape velocity which is numerically equal to 11.2 km per sec.
A direct answer is that the voyager in the question is going to be experiencing 1g of acceleration due to gravitational effect regardless of velocity. And that's all. Here's why. We didn't see our traveler lift off. That's where he gets smooshed back in his seat. That's not part of the question. We are joining him in flight where he is moving vertically at some velocity which, though it wasn't quantified, was specified as constant. The key is the constant velocity. That means no vertical acceleration from the rocket. No vertical acceleration from the rocket and only gravity pulling down means the effect of gravity has zero help from the rocket in smooshing our traveler back in his seat, so he is experiencing 1g of acceleration, and all of it due to gravity. To see another view, apply magic. Picture the rocket moving along horizontally like a car cruising down a highway. (Magic, remember? Picture it.) The rocket is moving at a fixed speed. Is the traveler being pushed back in his seat? Would the traveler in a car be pushed back in his seat if traveling at a fixed speed down a road regardless of speed? No, he wouldn't. Neither is our traveler in his rocket. Now more magic. Instantly (in zero time) our traveler's rocket is traveling up at the same (unspecified) fixed speed. (No turning, just instantaneous change of direction.) The only thing that has changed is direction. Oh, and gravity is now pulling down on our traveler at an amount based on his mass and not on the change of speed of the rocket. There is no acceleration component due to the rocket changing speed. The only acceleration our traveler is experiencing is due to gravity, and that will be 1g of down force. Regardless of the velocity.
Of course. You need to go back and review the definitions of those terms. Acceleration is the rate at which velocity changes. If velocity is not changing, then there is no acceleration. But the velocity doesn't have to be zero just because it's not changing. Velocity is the speed of an object and the direction in which it's moving. If it's moving at a constant speed in a straight line, then it has plenty of velocity. But since the speed isn't changing and the direction isn't changing, there's no acceleration. If acceleration comes along somehow ... such as by igniting a rocket motor, or gravity pulling the object downward, or someone reaching out and giving the object a push, then the speed or direction may change, and that'll be a change of velocity.
Exactly the same way it takes off from the earth. Gravity on the moon is so relativistically low that the propulsion required to reach an escape velocity is very very low compared to the earth.
Escape velocity.
By expelling hot gasses extremely fast from the rocket nozzle. Due to the conservation of momentum, expelling mass at high velocity causes the rocket to gain momentum and therefore velocity.