Different. Momentum is velocity * mass.
No, because momentum depends on velocity and mass so they may have the same velocity but if they have different masses then they will have different momenta. (momenta is the plural form of momentum.)
The momentum product can be the same with different velocities; m1V=m2rV thus m1/m2=r ratio with V1=rV1.
Momentum is not just mass. Momentum is the product of mass x velocity.
Momentum is defined as the "Mass in Motion". It is a Vector quantity. It depends on two variables (Object Mass and Velocity) . Its direction is same as objects velocity direction. In physics momentum is required to specify the motion of the object . If two bodies of same masses having different velocities have different momentum , in a similar way bodies of different masses having same velocity have different momentum. So , in order to describe the motion of object clearly one of the tool in classical mechanics is momentum
In the same direction. Both momentum and velocity are vectors.
The slow moving train has a much higher mass than the high-speed bullet, but the bullet has a faster velocity than the slow moving train so their momentum is the same.
Momentum is velocity times mass, so, in order for two cars to have the same momentum at the same velocity, they must have the same mass. Engine capacity has nothing do do with the equation.
Momentum is mass x velocity; velocity has a direction, therefore momentum has a direction.Momentum is mass x velocity; velocity has a direction, therefore momentum has a direction.Momentum is mass x velocity; velocity has a direction, therefore momentum has a direction.Momentum is mass x velocity; velocity has a direction, therefore momentum has a direction.
The answer is velocity.
No, momentum is directly proportional to velocity, and in the same direction..
Velocity!
That would depend on their velocity (speed with direction), since the formula for momentum is momentum=Mass*Velocity. If they are moving at the same Velocity, the heavier of the two would have greater momentum.