2C8H18 + 25O2 -> 8CO2 + 18H2O
No. I can see right off that you have 16 atoms of carbon on the reactant (left) side and only 8 atoms of carbon on the product (right) side. Let's see.
2C8H18 + 25O2 -> 16CO2 + 18H2O
Now it is balanced.
The combustion reaction of octane is:2 C8H18 + 25 O2 = 16 CO2 + 18 H2OSo, the number of oxygen molecules is 25.The isomer trimethylpentane is used as standard in octane rating: the end of the scale at 100.
I don't know ...........cheesecake its the combustion of octane
octane + oxygen --> water + carbon dioxide
2c8h18 + 25o2 ---> 16co2 + 18h2o
Reaction of octane combustion- 2C8H18+25O2= 16CO2+ 18H2O That mean from 228g octane (16*22.4dm3) = 358.4dm3 of CO2 is produced. {because volume of each mole is 22.4dm3} Now, from 10 kg of octane produced volume of CO2 is = (358.4*10000)/228 =(15719.298 dm3/1000)m3 =15.719 m3.
The combustion reaction of octane is:2 C8H18 + 25 O2 = 16 CO2 + 18 H2OSo, the number of oxygen molecules is 25.The isomer trimethylpentane is used as standard in octane rating: the end of the scale at 100.
I don't know ...........cheesecake its the combustion of octane
This is a typical combustion reaction in that it involves a hydrocarbon reacting with oxygen. The products of combustion reactions are always carbon dioxide and water, just in varying quantities.
2c8h18 + 25o2--> 16co2 + 18h2o
2C8H18 + 12.5O2 --------> 16CO2 + 18 H2O *As O2 is diatomic you can use half multiples when balancing.*
the reaction is from the combustion of Octane
Balanced equation. 2C8H18 + 25O2 -> 16CO2 + 18H2O 5.5 moles C8H18 (25 moles O2/2 moles C8H18) = 68.75 moles O2 needed
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
octane + oxygen --> water + carbon dioxide
2C8H18 + 25O2 = 16CO2 + 18H2O Of course some times the reaction yields carbon monoxide as well, most of which is changed to CO2 in the catalytic convert.
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
2C8H18 + 17O2 --> 16CO + 18H2O C8H18 + 8.5O2 --> 8CO + 9H2O half equation, halfs can be used in combustion.