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How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
How many moles of H2O are produced when 0.468 mol of octane is burned?
First write down the BALANCED reaction eq'n. Octane + oxygen = Water + Carbon Dioxide. 2CH3(CH2)6CH3 + 25O2 = 18H2O + 16CO2 The molar ratios are 2:25 :: 18:16 So '2' moles of octane produces 18 moles of water. So by equivlance 0.468 : x :: 2 : 18 Algebraically rearrgange x = (0.468/2) X 18 => x = 0.234 x 18 = > x = 4.212 moles water produces.
What weight of water is produced burning 19.8grams of octane?
The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1 The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g 19.8 g of octane is 114.23/19.8 moles so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water
How many moles of HCl are needed to react with 2.3 moles of Zn in the following reaction?
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
Does fossil fuels produce carbon dioxide gas and water when they burn?
Yes, if they are perfectly pure and burn correctly. Otherwise there is additional nasty stuff in small quantities. Added: 2C8H18 + 25O2 --> 16CO2 + 18H2O A reaction showing the simplified burning of gasoline ( C8H18 = octane ) and the many moles of carbon dioxide and water produced.
How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
How much CO2 in m3 is formed from burning 10.000 kg octane?
Reaction of octane combustion- 2C8H18+25O2= 16CO2+ 18H2O That mean from 228g octane (16*22.4dm3) = 358.4dm3 of CO2 is produced. {because volume of each mole is 22.4dm3} Now, from 10 kg of octane produced volume of CO2 is = (358.4*10000)/228 =(15719.298 dm3/1000)m3 =15.719 m3.
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
How many moles of H2O are produced when 0.468 mol of octane is burned?
First write down the BALANCED reaction eq'n. Octane + oxygen = Water + Carbon Dioxide. 2CH3(CH2)6CH3 + 25O2 = 18H2O + 16CO2 The molar ratios are 2:25 :: 18:16 So '2' moles of octane produces 18 moles of water. So by equivlance 0.468 : x :: 2 : 18 Algebraically rearrgange x = (0.468/2) X 18 => x = 0.234 x 18 = > x = 4.212 moles water produces.
What weight of water is produced burning 19.8grams of octane?
The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1 The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g 19.8 g of octane is 114.23/19.8 moles so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water
Which is the limiting reactant when 3.00 moles of calcium are reacted with 8.00 moles of water in the following equation?
To determine the limiting reactant, you must compare the moles of each reactant to the stoichiometry of the reaction. The balanced equation is essential to determine the ratio of moles needed for the reaction. In this case, 3.00 moles of calcium and 8.00 moles of water are given, and you can find which reactant limits the reaction by finding out which reactant would require more moles for complete reaction based on the stoichiometry.
How many moles of ammonia are produced from the reaction of 90.0 L of nitrogen?
8,038 moles of ammonia were produced.
According to the following balanced reaction how many moles of NO are formed from 8.44 moles of NO2 if there is plenty of water present?
If the reaction is not specified, we can't determine the exact moles of NO formed from NO2 based on this information alone. The reaction and stoichiometry are needed to calculate the moles of NO produced from 8.44 moles of NO2.
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
How many moles of CS2 form when 3 moles of SO2 reacts?
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How to find moles from volume in a chemical reaction?
To find moles from volume in a chemical reaction, you can use the formula: moles volume (in liters) / molar volume (22.4 L/mol at standard conditions). Simply divide the volume of the gas by the molar volume to calculate the number of moles present in the reaction.
