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How do you add and subtract rational numbers?
A rational number is a number of the form p/q where p and q are integers and q > 0.If p/q and r/s are two rational numbers thenp/q + r/s = (p*s + q*r) / (q*r)andp/q - r/s = (p*s - q*r) / (q*r)The answers may need simplification.
Prove that if a and b are rational numbers then a multiplied by b is a rational number?
If a is rational then there exist integers p and q such that a = p/q where q>0. Similarly, b = r/s for some integers r and s (s>0) Then a*b = p/q * r/s = (p*r)/(q*s) Now, since p, q r and s are integers, p*r and q*s are integers. Also, q and s > 0 means that q*s > 0 Thus a*b can be expressed as x/y where p and r are integers implies that x = p*r is an integer q and s are positive integers implies that y = q*s is a positive integer. That is, a*b is rational.
L is not as tall as P or R but is taller than S and Q Q being shorter than R S is shorter than R who is shorter than P who is taller than Q Who among P Q R and S is the shortest?
The answer is Q.
How do you rewrite this equation Q equals R over S...to solve for R and S..i dont get it?
If Q = R/S then R = QxS and S = R/Q You can easily replace the letters with numbers such as Q = 2, R = 6 and S = 3 and then write out all three equations and you'll see that they make sense.
Which letter is next but one after q?
In the alphabet the letter that comes after Q is the letter R. The letter that comes before Q would be P.
What are the rules for multiplying rational numbers?
p/q * r/s = (p*r)/(q*s)
What is the answer to add q and p triple the result then divide r by s?
It is 3*(q + p)/(r + s)
A fruit beginning s?
Satsuma
How do you use the LCM to write fractions with a common denominator?
Suppose you have the fractions p/q and r/s. Let the LCM of q and s be t.Then t is a multiple of q as well as of s so let t= q*u and t = s*v Then p/q = (p*u)/(q*u) = (p*u)/t and r/s = (r*v)/(s*v) = (r*v)/t have the same denominators.
Can the product of two rational numbers be irrational?
No.Suppose a and b are two rational numbers.Then they can be written as follows: a = p/q, b = r/s where p, q, r and s are integers and q, s >0.Then a*b = (p*r)/(q*s).Using the properties of integers, p*r and q*s are integers and q*s is non-zero. So a*b can be expressed as a ratio of two integers and so the product is rational.
How do you rename as improper faction As a mixed number?
Suppose the improper fraction is p/q, then if q goes into p r times with a remainder of s, thenp/q = r s/q
An equation that shows two ratios are equivalent?
Two ratios, p/q and r/s (q and s non-zero) are equal if p/q - r/s = 0.
