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Q: Is there a number evenly divisible by 10 but not evenly divisible by 5?

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Not always because as for example 25 is not evenly divisible by 10 but it is evenly divisible by 5

Any number that ends in a zero is divisible evenly by 5 and 10

No, the number 566 is not evenly divisible by 5. Only numbers that end in 5 or 0 are evenly divisible by 5. If you subtract 1 from 566 you then have a number that is evenly divisible by 5, which is 565. 565/5 = 113.

The number 58 is not evenly divisible by 5.

Yes, as 10 is evenly divisible by 5.

No because as for example 25 is evenly divisible by 5 but not by 10

Every number is divisible by any non-zero number. However, 1407 is not evenly divisible by 5.

Every whole number that ends with a 0 or a 5 is evenly divisible by 5.

45.

Only divisible by 5 evenly

Yes. Every number is divisible by every other number except 0. Therefore the answer is yes. If you actually meant is 834 evenly divisible by 2, 3, 5, 9 or 10 [with no remainder], then the answer is also yes because 834 is evenly divisible by both 2 and 3. It is not evenly divisible by 5, 9 and 10 but the 'or' in the question implies that it only need be divisible by one or more of the values, not necessarily all of them. If you really meant all of them, then the answer is no. In short, 834 is evenly divisible by 2 and 3, but not by 5, 9 or 10. It is obviously evenly divisible by 2 since 834 is an even number: 834 / 2 = 417. It is obviously evenly divisible by 3 since 834 / 3 is 278. It is obviously not evenly divisible by 5 since the least-significant digit (4) is neither 5 nor 0. It is obviously not evenly divisible by 9 because the digits do not recursively add up to 9. That is, 8 + 3 + 4 = 15 => 1 + 5 = 6. Ergo, 6 <> 9 therefore 834 is not evenly divisible by 9. It is obviously not evenly divisible by 10 since the least-significant digit (4) is not 0.

Any whole number ending with 5 or 0 is evenly divisible by 5.

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