Not always because as for example 25 is not evenly divisible by 10 but it is evenly divisible by 5
Any number that ends in a zero is divisible evenly by 5 and 10
No, the number 566 is not evenly divisible by 5. Only numbers that end in 5 or 0 are evenly divisible by 5. If you subtract 1 from 566 you then have a number that is evenly divisible by 5, which is 565. 565/5 = 113.
The number 58 is not evenly divisible by 5.
No because as for example 25 is evenly divisible by 5 but not by 10
Yes, as 10 is evenly divisible by 5.
Yes. Every number is divisible by every other number except 0. Therefore the answer is yes. If you actually meant is 834 evenly divisible by 2, 3, 5, 9 or 10 [with no remainder], then the answer is also yes because 834 is evenly divisible by both 2 and 3. It is not evenly divisible by 5, 9 and 10 but the 'or' in the question implies that it only need be divisible by one or more of the values, not necessarily all of them. If you really meant all of them, then the answer is no. In short, 834 is evenly divisible by 2 and 3, but not by 5, 9 or 10. It is obviously evenly divisible by 2 since 834 is an even number: 834 / 2 = 417. It is obviously evenly divisible by 3 since 834 / 3 is 278. It is obviously not evenly divisible by 5 since the least-significant digit (4) is neither 5 nor 0. It is obviously not evenly divisible by 9 because the digits do not recursively add up to 9. That is, 8 + 3 + 4 = 15 => 1 + 5 = 6. Ergo, 6 <> 9 therefore 834 is not evenly divisible by 9. It is obviously not evenly divisible by 10 since the least-significant digit (4) is not 0.
Every whole number that ends with a 0 or a 5 is evenly divisible by 5.
Every number is divisible by any non-zero number. However, 1407 is not evenly divisible by 5.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
Only divisible by 5 evenly
No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5
Any number evenly divisible by an even number is also even. A number evenly divisible by an odd number (such as 5) could be either even or odd.
Every number divisible by 10 is divisible by 5.
Any whole number ending with 5 or 0 is evenly divisible by 5.
5 is a prime number. It is only evenly divisible by itself and one.11 is a prime number. It is only evenly divisible by itself and one.
by 2 is 171 by 3 is 114 by 4 is not evenly divisible nor by 5, by 6 it is evely divisible 57 times, by 9 its 38 not evenly by 10.
2 is a prime number. It is only evenly divisible by itself and one.3 is a prime number. It is only evenly divisible by itself and one.5 is a prime number. It is only evenly divisible by itself and one.
10 ÷ 2 = 510 ÷ 5 = 2Therefore, the answer is ten
655 is evenly divisible by 1, 5, 131 and 655.
475 is evenly divisible by 5, but not by 2, 3, 4, or 10.
No. 15, 25, 35, and 1675 are divisible by 5, but not by 10. However, every number divisible by 10 is also divisible by 5.
3 is a prime number. It is only evenly divisible by itself and one.5 is a prime number. It is only evenly divisible by itself and one.