Yes,there is game called Red Ball 4,on ,,Not Doppler,,.It will come out 1st november.
If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.If you pot a red ball, normally you get one point. If a ball is knocked off the table, your opponent will get at least 4 points.
17 out of 21
1/9, 1/10 red either 1/10, 0r 2/10
The probability of getting on the first draw a black ball is: P(B1) = 3/7. The probability of getting a red ball given the event of drawing a black ball on the first draw is: P(R2│B1) = 4/6. The probability of drawing a black ball on the first draw and a red ball on the second draw is: P(B1UR2) = P(B1)∙P(R 2│B1) = (3/7)∙(4/6) = 0.2857... ~ 0.286 ~ ~ 28.6%
There are 7 balls in total.4 are red and 1 is the blue "5" ball. Thus there are five balls out of the seven which meet the criteria and therefore the odds must be 5/7.The probabilities are mutually exclusive (i.e. you can not both draw a red ball and the "5" ball at the same time as the "5" is blue) so you just add the probabilities of each together.Probability of drawing a red ball = 4/7 (4 of the 7 balls are red)Probability of drawing the "5" ball = 1/7 (1 of the 7 balls is the "5" ball)Overall probability = 4/7 + 1/7 = 5/7
Drawing one red ball out of a bag that contains 3 red balls and 4 green balls is 3 in 7. If we are to randomly select one ball out of the bag and replace it (I assume with the same ball) then there are still 3 red balls and 4 green balls. The odds are still 3 in 7. It doesn't matter how many times you draw. Every time you draw a ball you have a 3 in 7 chance of pulling out a red ball.
I have no idea yet oh yeah on Doppler I think
1/4
That depends. Picking a red ball is 4/9 Picking a green ball is 3/9 = 1/3 Picking a yellow ball is 2/9. Picking a ball is 9/9 or 1 because you'll always take one.
#1 Dip the ball in red #2 Do the ears with the plungers #3 Dip the ball in blue #4 Put the red dot on the ball #5 Plunger the nose #6 Spray paint the eyes on
It is (7+4)/(7+5+4+4) = 11/20
12