Skitty:P: Those codes are very useful below, but this is for the Lucario Rank
0213c140 3b9aca00
Yes, there is a code, although I am not so sure about red rescue team for this one. Is all you have to do is press up + L to go up one floor, or just hold them to constantly go up floors. Now you won't just go up, the game will think that you are on the floor, so you really have to find the stairs after you choose what floor you want, and the stairs will add on to your chosen floor. So take your floor, and subtract 1 from it, then go to the stairs. The code for this is:
74000100 FF00000C A cool trick for this is to go to the floor right before thefloor
94000130 FDBF0000 a legendary Pokemon is on. But save beforehand .
DA000000 021153E4 This is a great way to get all of the legendaries,
D4000000 00000100 how do you think I got them all in two days(not) mew
D7000000 021153E4 though)? I did use the full storage code and withdrew a
D2000000 00000000 friend bow to help me.
There is also a code for going down, but all it did to me was take me to Groudon while I was in meteor cave finding Deoxys. But there is a code that ends the dungeon. You just have to press L+R right when you press proceed on the stairs, then it will be over. That code is:
94000130 FCFF0000
221153E5 000000FF
D0000000 00000000 These codes are very useful. Well, I hope these help!
yes there is
0213c140 3b9aca00
erm u get the Pokemon mystery dungeon blue codes with action replay :D
The action redplay does not work with this game.
There is no Lucario Team its just a name used plus there all propble dead there we a rescue team a long time ago. NO! You can get him you just have to get all the friend areas including the ones you can't buy from Wigglytuff's shop. You can get some from missions. Or if you have an action replay/gameshark there's some websites that have codes for friend areas too.
pikachu
No search a life
by beating the game
Action Replay.
no but u can get lucario rank with 15000 rescue points
yes if you have an action replay
nope you'll have to wait.