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I'm trying to give you a simple example. Which hope will be able to make you understand that thing. We read physics in our language. So I can make some mistakes to write that in English... But I hope I won't be mistaken. By the way here it is...

Suppose, There is a simple oscillator what is moving under the angles of 4 degrees. When it is in his height position then we know that it stops for a moment and then comes back to the equilibrium position. So in the height position it's velocity is 0 m/s. (cause it stops.) Suppose it's 1st velocity or the velocity in the equilibrium position is "v" and in that position the last velocity is 0. so we can calculate it's acceleration like that

a = (last velocity-1st velocity)/time

so a = (0-u)/t = - u/t, what is the maximum acceleration of a this body, (-) sign means the acceleration is gonna go down.

But when it is coming back to the equilibrium position, it's velocity goes up.. And in the equilibrium position it's velocity is maximum. Then the velocity decreases again. so in the equilibrium position the velocity is maximum, in the equilibrium position which is "v". so it's acceleration will be

a= v-v/t = 0/t = 0, that means the acceleration is zero when the velocity is maximum...

That means the acceleration of a body can be zero when the velocity is maximum and the velocity can be zero when the acceleration is maximum.

[Note: Always remember, to start to calculate from the equilibrium position. Because the oscillation starts from the equilibrium position. And what I said is the most simple statement. It can also be described by the equations of the a simple harmonic oscillations]

- by JAS

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12y ago

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