fe + 2 O ------> FeO2 iron II oxide
Rust.
FEO2
Kind of reddish brown. FeO2 is commonly called rust.
FeO2 is a solid. It is a compound composed of iron (Fe) and oxygen (O) atoms, and it typically exists in a solid form at room temperature and pressure.
Its difficult to understand your question, I can make an assumption (although your stoichiometry is off). Are you asking about Iron Oxide compounds? Iron is a transition metal, abbreviated "Fe." It has two oxidative states, +2 and +3--often written as Fe (II) and Fe (III). If you have Fe(II) oxide, FeO, it would be called "ferrous oxide." If you have Fe(III) oxide, Fe2 O3, it would be called "ferric oxide." The other forms in your question aren't correct and I cannot answer them.
no Iron Oxide [Rust] is most often represented as Fe2O3.
It's an oxidation reaction forming iron oxide (rust). Basically: iron + oxygen = iron oxide Iron, (Fe) is an element and react easily with the element Oxygen (O2) the resultant material is a compound known as rust or iron oxide, (FeO2) this proces is known as oxidization.
A molecule of Fe2O3 contain 5 atoms; two molecules contain 10 atoms.
AgO2 is silver oxide. An other more common example of an oxide is iron oxide, FeO2, more commonly known as rust! Most metals are not pure in their natural states, but rather are found in an oxidized state.
To calculate the mass of FeO2 produced, we first need to find the number of moles of O2 using the ideal gas law: PV = nRT. At STP, 1 mole of gas occupies 22.4 L, so 50.0 L of O2 is 50.0/22.4 = 2.23 moles. The balanced equation for the reaction will tell you the stoichiometry needed to calculate the mass of FeO2 produced.
Iron oxide, commonly known as rust, is formed when iron combines with oxygen in the air through a chemical reaction. Rust has a reddish-brown color and weakens the structural integrity of iron over time.
The empirical formula of the iron oxide compound is Fe₂O₃. This is determined by dividing the percentage of each element by its molar mass to find the ratio of atoms in the compound.