Yes. It contains divalent zinc cations and divalent sulfide anions.
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No, the bonds in zinc sulfide have very little ionic character (19% ionic character). The confusion lies is the fact that ZnS has a high melting point (it actually sublimes at 1185C).
The problem is that bonding is vastly oversimplified and any substance with a high melting point or containing a metal and a nonmetal are assumed to be ionic. Such is not the case.
The bottom line is that it is the structure of the substance -- network vs discrete molecule -- that determines properties like MP and BP, not whether the bond is either hypothetically "ionic" or "covalent".
Zn(NO3)2 is an ionic compound called zinc nitrate.
yes
The compound formula for zinc nitrate is Zn(NO3)2.
Zn(NO3)2 is an ionic compound called zinc nitrate.
There are 3 elements in ZnSO4: zinc (Zn), sulfur (S), and oxygen (O).
The chemical formula for the ternary compound composed of Zn2+ and OH- ions is Zn(OH)2.
Zn3P2 is a binary ionic compound composed of zinc (Zn) and phosphorus (P) ions. It forms when Zn and P react together in a chemical reaction, creating a compound with a 2:3 ratio of zinc to phosphorus atoms.
Nitrate is a polyatomic ion. Zn(NO3)2
Zn(C2H3O2)2 is an ionic compound. Ionic compounds typically consist of a metal cation (Zn in this case) and a non-metal anion (C2H3O2- in this case).
New compound create - HCL + Zn = Zcl + 1/2 Hn ZCL - Zuniclo Hn - Hino
The formula for zinc nitride is Zn3N2. It is formed when zinc reacts with nitrogen to create a compound composed of zinc cations and nitride anions.
To find the oxidation number of zinc (Zn) in zinc nitrate (Zn(NO3)2), you start by recognizing that nitrate (NO3) has a charge of -1. Since there are two nitrate ions in the compound, the total negative charge is -2. To balance this, the oxidation number of zinc must be +2. Therefore, the oxidation number of Zn in Zn(NO3)2 is +2.