answersLogoWhite

0

Jan Timothy Tria Tan

Updated: 11/6/2022
User Avatar

Wiki User

12y ago

Best Answer

Jan Timothy Tan is a learner in Angelicum college ys 8 Moderator Mr.Aballe

Born in November 20 1995

had 4 girlfriends

Micah Dulce Benardez the recent

Leanne Ciara Nacua

Shaira Mae Dy

Nicole Ching

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Jan Timothy Tria Tan
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What rhymes with Ann?

can, man, ran, pan, van, tan, ban, fan, Jan, Dan, nan


What rhymes with vans?

Can, ban, fan, man, pan, ran, tan, than, plan, clan, span,ban, can, dan, fan, han, jan, man, pan, ran, tan


Tan 9 plus tan 81 -tan 27-tan 63?

tan(9) + tan(81) - tan(27) - tan(63) = 4


What is a antonym of pale?

Tan Tan


What is tan20tan32 plus tan32tan38 plus tan38tan20?

This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1


If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?

tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).


When was Tan Cerca...Tan Lejos created?

Tan Cerca...Tan Lejos was created in 1975.


What is the airport code for Tan Tan Airport?

The airport code for Tan Tan Airport is TTA.


What is the exact trigonometric function value of cot 15 degrees?

cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)


Which is greater tan 1tan2 tan3 .arrange them in descending order?

If the angles are measured in degrees or gradians, then: tan 3 > tan 2 > tan 1 If the angles are measured in radians, then: tan 1 > tan 3 > tan 2.


How do you find the value of tan 135?

tan(135) = -tan(180-135) = -tan(45) = -1


What rhymes with cans?

Ban, Stan, van, nan, Dan, pan, ran, Jan, man, land, fan, Nan, span, scan, tan, Gran, plan, an, bran, Ann, Anne, Franman, fan, pan, etc.anbanDanfanJanmanpanrantanvanMany thing ryme with can. It depends on what you are going to do with it if it is for a poem you don't really have to make it ryme, but these are a few words that ryme with can. Pan, Man, Blan, Ran. Those are just a few though.In thinking about this an- swer, I'd use the usual ban- ter, but I thought I would be real fan- cy, and show that I have some man- ners, but this answer I think you should panban, dan, man, pan, ran, tan, fan, nan, van,pan,man,ran,fan,dan,jan,Sorry guys I did my best! :)an,ban,dan,stan, ran,fan,jan,man,pan,tan,van.Pan,Dan,Man,Ran,Fan,Tan,and Vanan, ban, Dan, fan, man, Nan, pan, ran, Stan, tan, van