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Java program to identify duplicates in a sequence of ten intgers?
Chuckster1
Compare each number with all the previous numbers. For example:
boolean duplicateExists = false;
int duplicateNumber;
for (int i = 0; i < 10; i++)
for (int j = 0; j < i; j++)
if (myNumbers[i] == myNumbers[j])
{
duplicateExists = true;
duplicateNumber = myNumbers[i];
}
Compare each number with all the previous numbers. For example:
boolean duplicateExists = false;
int duplicateNumber;
for (int i = 0; i < 10; i++)
for (int j = 0; j < i; j++)
if (myNumbers[i] == myNumbers[j])
{
duplicateExists = true;
duplicateNumber = myNumbers[i];
}
Compare each number with all the previous numbers. For example:
boolean duplicateExists = false;
int duplicateNumber;
for (int i = 0; i < 10; i++)
for (int j = 0; j < i; j++)
if (myNumbers[i] == myNumbers[j])
{
duplicateExists = true;
duplicateNumber = myNumbers[i];
}
Compare each number with all the previous numbers. For example:
boolean duplicateExists = false;
int duplicateNumber;
for (int i = 0; i < 10; i++)
for (int j = 0; j < i; j++)
if (myNumbers[i] == myNumbers[j])
{
duplicateExists = true;
duplicateNumber = myNumbers[i];
}
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoCompare each number with all the previous numbers. For example:
boolean duplicateExists = false;
int duplicateNumber;
for (int i = 0; i < 10; i++)
for (int j = 0; j < i; j++)
if (myNumbers[i] == myNumbers[j])
{
duplicateExists = true;
duplicateNumber = myNumbers[i];
}
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Is removing duplicate file on computers dangerous?
It's only dangerous if you delete duplicate files without thinking and don't use a good software for finding duplicates. For example, some duplicate finders compare files by name only and thus delete files that are not actually duplicates. If you want to stay completely safe, get an advanced program like Easy Duplicate Finder (or a similar program with similar features) and select "Compare files by content" in the settings (or "byte-by-byte comparison" depending on the program). That way the duplicate finder will only show you exact duplicates.
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