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Q: LHow did large mining companies succeed?
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What is solubility of chromium?

If At 25 Degrees C, the molar solubility of barium chromate in water is 1.1 x 10^-5 M. Here is how you would find the solubility in grams per liter.First: You must know the molar mass of Barium Chromate To continue. Look at your periodic Table.[BariumChromate Molar mass=253.37 g/mol]*Get this by adding together atomic number of each element in BaCrO4*253.37= Ba+Cr+O(4), or 137.33+52+16(4)*Take 1.1 x 10^-5 M and divide by molar mass of Barium Chromate1.1 x 10^-5 mol/L x 253.37 =0.002787Answer in grams per liter to three significant figures=2.787 x 10^-3 g/LHow many liters of water are required to dissolve 1 of barium chromate?*take 1gram BaCrO4 / 2.787 x 10^-3 g/L --------> Grams Cancel=2.787 x 10^-3 LAnswer in liters to three significant figures =359.71 LitersWhat is the solubility of barium chromate in parts per million?*parts per million = Grams of Solute/grams of solution X 10^6 (which is ppm)2.787 x 10^-3g/L x 1L/1000g x 10^6 = 0.02779, or 2.78 x 10^-2ppmAnswer in parts per million to three significant figures=2.78ppm**For dilute aqueous solutions, ppm is equivalent to units of mg/l