Memory page.
Pages
Memory manager works with pages and segments;these are different things, don't confuse them.
If a 4k segment is stored at address 2000H, the last address will be 2FFFH.
The 2147 memory is 4096 X 1 bit static RAM. You need 8 chips to form 4K x 8.
4K (4096) of addressable space is defined by 12 bits of address space, because 212 = 4096.
You need 12 address lines to access 4K of memory. 212 = 4096. log2 (4096) = 12.
4k it is...$4.000.00...
-4k-2=10 -4k=10+2 -4k=12 k=-3
4k-100 = -96
8-4k = 40 (4k-8) - 8 = 40-8 4k = 32 4k/4 = 32/4 k =8
4k-64 = -60
Yes, 4K is $4000.