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N C be D to 0?

Updated: 10/19/2022
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Standa

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15y ago

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nothing can be divided to 0

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Q: N C be D to 0?
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How can you write a c program to find maximum element in row and minimum element in column of a matrix?

#include <stdio.h> main() { int m, n, c, d, A[10][10],temp=0; printf("\nEnter the number of rows and columns for matrix A:\n"); scanf("%d%d", &m, &n); printf("\nEnter the elements of matrix A:\n"); for ( c = 0 ; c < m ; c++ ) for ( d = 0 ; d < n ; d++ ) scanf("%d", &A[c][d]); printf("\nMatrix entered is:\n"); for ( c = 0 ; c < m ; c++ ) { for ( d = 0 ; d < n ; d++ ) printf("%d\t", A[c][d]); printf("\n"); } printf("\n\nMaximum element of each row is:\n"); for(c=0;c<m;c++) { for(d=0;d<n;d++) { if(A[c][d]>temp) temp=A[c][d]; } printf("\n\t\tRow %d: %d",c+1,temp); temp=0; } temp=A[0][0]; printf("\n\nMinimum element of each coloumn is:\n"); for(c=0;c<n;c++) { for(d=0;d<m;d++) { if(A[d][c]<temp) temp=A[d][c]; } printf("\n\t\tColoumn %d: %d",c+1,temp); temp=A[d][c] ; } return 0; }


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Sorry to delete the previous version of this program, but this one is much more concise and sophisticated. I have written this program for a 3*3 matrix, but if you want to change it, just enter additional variables to store the order of the matrix and then replace the "3"s of the program with them as needed. It's easy. So here we go:#include#includevoid swap(int *x,int *y);main(){int i,j,k,m,n;int matrix[3][3];printf("Enter the matrix: \n\n");for (i=0;i


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N C be D to O?

Nothing can be Divided to 0


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