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What is the experimental probability of choosing a green marble if there are 7 red 9 yellow 14 green and 10 purple?
To find the experimental probability of choosing a green marble, first calculate the total number of marbles: 7 red + 9 yellow + 14 green + 10 purple = 40 marbles. The probability of choosing a green marble is the number of green marbles divided by the total number of marbles, which is 14 green / 40 total = 0.35. Thus, the experimental probability of choosing a green marble is 0.35, or 35%.
What is the probability of choosing blue marble followed by a green marble from a bag containing 5 blue 5 green and 5 red marbles?
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
What is the probabilityof choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
The probability of choosing a green marble from this jar would be 6/15. You get this answer by adding up the sum of all the marbles.
What is the probability of choosing a marble that is not blue out of 5 red and 6 green?
100%
What is the probability of choosing a red marble from a jar 5 red 6 green and 4 blue marble?
1/3 or 33%
Explain how to find the probability of choosing a green marble from a bag of marbles containing 5 green 3 blue 6 red and 12 white?
If you pick only one marble from the bag, at random, it can be any one of 26 marbles. Out of these, 5 of the marbles are green. Thus, there are 26 possible outcomes out of which 5 are favourable - to the event that the marble is green. Therefore the probability of a green marble is 5/26. The calculations become more complicated if you consider choosing a green marble in several attempt: it depends on whether or not the marbles are replaced before the next one is picked.
What is the sample space for choosing a marble out of a bag with 3 green 4 blue and 7 purple marbles?
green blue purple answer
What is the probability of not choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
What is the probability of choosing a green marble from A jar containing 4 red 6 green and 5 blue marbles?
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?
The probability of drawing a white marble is .46
There is 3 bags with 2 marbles one green and one blue what is the probablitly of choosing one blue marble one green marble and then another blue marble?
It is not explicitly stated in the question, but it is assumed that you draw one marble from each bag. In this case, you have unrelated sequential probability, similar to tossing three coins. The answer is 0.53 or 0.125.
What is the probability of choosing a marble that is not blue if a jar contains 4 red 7 green and 5 blue marbles?
5:16
