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pH + pOH = 14.

So pOH = 14 - 10.95 = 3.05

pOH = -log[OH-]

[OH-] = 8.91 x 10-4 M

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11y ago
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13h ago

The hydroxide ion concentration of a solution with a pH of 10.95 is 1.26 x 10^-11 mol/L. This can be calculated using the formula [OH-] = 10^(-pH).

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10y ago

It is 4.6x10^-11M

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Q: OH- of a solution which has a pH equals 10.95?
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Related questions

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