By an indirect proof. Assuming the square root is rational, it can be written as a fraction a/b, with integer numerator and denominator (this is basically the definition of "rational"). If you square this, you get a2/b2, which is rational. Hence, the assumption that the square root is rational is false.
This is impossible to prove, as the square root of 2 is irrational.
The square root of 2 is 1.141..... is an irrational number
Because 3 is a prime number and as such its square root is irrational
It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
Yes. The square root of a positive integer can ONLY be either:* An integer (in this case, it isn't), OR * An irrational number. The proof is basically the same as the proof used in high school algebra, to prove that the square root of 2 is irrational.
The square root of 94 is an irrational number
The square root of 200 is irrational.
irrational
Irrational (and a multiple of i), as the square root of 255 is irrational.
The square root of 11 is an irrational number
If the positive square root (for example, square root of 2) is irrational, then the corresponding negative square root (for example, minus square root of 2) is also irrational.