Here are two functions which you can use to find min and max:
double min(const arr[], int arrSize)
{
double minimum = arr[0];
for (int j = 0; j < arrSize; j++)
{
if (minimum > arr[j])
{
minimum = arr[j];
}
}
return maximum;
}
double max(const arr[], int arrSize)
{
double maximum = arr[0];
for (int j = 0; j < arrSize; j++)
{
if (maximum < arr[j])
{
maximum = arr[j];
}
}
return maximum;
}
Choose the lowest of the exponents. The GCF of x3 and x5 is x3
It is infinite but the lowest common multiple is 4500
Start with the lowest prime factors 2, 3, 5, 7 etc and work up.
Find the GCF of the numerator and the denominator and divide them both by it. If the GCF is 1, the fraction is in its simplest form.
To find the lower extreme, you need to identify the smallest value in a data set. To find the upper extreme, you need to identify the largest value in the data set. These values represent the lowest and highest points of the data distribution.
first:you find the gcm(greatest common factor)wich is the lowest number that can go evenly into the numerator and the denominator. next:you devide both the numerator and the denominator by that gcm(greatest common factor)and walla!
To put 410 in the lowest terms, you need to find the greatest common divisor (GCD) of 410 and reduce the fraction by dividing both the numerator and denominator by the GCD. Since 410 is a prime number, the lowest terms for 410 would be 410/1.
Well, honey, to find the value of an expression in lowest terms, you need to simplify it by dividing the numerator and denominator by their greatest common factor. It's like decluttering your closet - get rid of the unnecessary baggage! Once you've simplified the expression as much as possible, you've got yourself the value in lowest terms. Now go forth and conquer those fractions, darling!
those where you find the greatest amount of unmet needs and easy to get into! [example, selling and installing photo voltaic panels on roof tops]
To express 1018 in its lowest terms, we need to find the greatest common divisor (GCD) between 1018 and any other number. Since 1018 is even, it is divisible by 2. Therefore, 1018 in lowest terms is 509/2.
It is easier to find the lowest common number, then getting the largest multiple of that that is under 10000. The LCM is 4680, x2 is 9360.
To find the greatest common factor and lowest common multiple of two numbers, you first need to split those numbers up into their prime factors. In this case: 8 = 2x2x2 12 = 2x2x3 The next step is to identify any common factors. In this case the common factors are two 2s. To find the greatest common factor, you multiply these together: 2x2 = 4. A quick way to find the lowest common multiple is to multiply the two original numbers together and divide by the greatest common factor. So 8x12/4 = 24. Thus 24 is the lowest common multiple.