Sure, you can write a function in C to convert a string to Pig Latin without using pointers by passing the string as a parameter and manipulating it directly within the function. You can split the string into words, check if a word starts with a vowel or consonant, and then apply the appropriate transformation following the rules of Pig Latin. Remember to allocate enough memory for the modified string to prevent buffer overflow.
In American Sign Language (ASL), the alphabet is represented using one-handed signs for each letter from A to Z. Each letter is formed by using specific handshapes and movements. It is a foundational skill in learning sign language.
The basketball swished through the net, scoring a perfect three-pointer.
In American Sign Language, the sign for 'plus' is made by using your dominant hand to make a flat palm facing upwards, then using your non-dominant hand to extend and tap the pointer finger of your dominant hand.
Here is an example of how you can find the vowels in a string using PHP: $str = "Hello World"; $vowels = preg_match_all('/[aeiou]/i', $str, $matches); echo "Vowels found: " . $vowels; This code snippet uses a regular expression to match all vowels (both uppercase and lowercase) in the string "Hello World" and counts how many vowels are found.
In American Sign Language (ASL), you would sign "we are" by using the sign for "we" which involves intertwining your fingers and pointing your thumbs outwards, and then signing "are" by extending your pointer finger and tapping it twice on your chest.
may...we can try by using pointer........... gets
We use a pointer to reference a string because a string is an array of characters where every element is a char (or a wchar_t if using UNICODE strings). Passing arrays by value would require the entire array to be copied, but passing a pointer variable to an array only copies the pointer, which is effectively the same as passing the array by reference. #include <iostream> int main() { char * psz = "hello"; // pointer to a null-terminated string. std::cout << psz; // pass the pointer (by value) to the insertion operator. return( 0 ); }
// Inventory Pointer // Demonstrates returning a pointer #include <iostream> #include <string> #include <vector> using namespace std; //returns a pointer to a string element string * ptrToElement(vector<string>* const pVec, int i); int main() { vector<string> inventory; inventory.push_back( "sword"); inventory.push_back( "armor"); inventory.push_back( "shield"); //displays string object that the returned pointer points to cout << "Sending the objected pointed to by returned pointer:\n"; cout << *(ptrToElement(&inventory, 0)) << "\n\n"; //assigns one pointer to another - inexpensive assignment cout << "Assigning the returned pointer to another pointer.\n"; string* pStr = ptrToElement(&inventory, 1); cout << "Sending the object pointed to by new pointer to cout:\n"; cout << *pStr << "\n\n"; //copies a string object - expensive assignment cout << "Assigning object pointed by pointer to a string object.\n"; string str = *(ptrToElement(&inventory, 2)); cout << "Sending the new string object to cout:\n"; cout << str << "\n\n"; //altering the string object through a returned pointer cout << "Altering an object through a returned pointer.\n"; *pStr = "Healing Potion"; cout << "Sending the altered object to cout:\n"; cout << inventory[1] << endl; return 0; } string * ptrToElement(vector<string>* const pVec, int i) { //returns address of the string in position i of vector that pVec points to return &((*pVec)[i]); }
shashi
Use "+". Example: String string = "does this answer " + "your question?";
You could try using piglatin its fun to use :D
length = strlen(string);
performing string operation using pointers
You don't be lazy and use your fingers!
Take out one letter, using a random number. Then replace the string with the new string, without the extracted letter. Repeat, until the remaining string has a length of zero. The extracted letters get added to a new string.Take out one letter, using a random number. Then replace the string with the new string, without the extracted letter. Repeat, until the remaining string has a length of zero. The extracted letters get added to a new string.Take out one letter, using a random number. Then replace the string with the new string, without the extracted letter. Repeat, until the remaining string has a length of zero. The extracted letters get added to a new string.Take out one letter, using a random number. Then replace the string with the new string, without the extracted letter. Repeat, until the remaining string has a length of zero. The extracted letters get added to a new string.
[ string toupper $str ] or [ string tolower $str ]
I guess you wanted to ask, why is it scanf ("%s", array)and not scanf ("%s", &array).Well, array is by definition a pointer to the first element: array = &array[0]