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Newton prove gravity by means of an apple falling on his head
your prove or disprove it.
You can not prove it true.
Prove that the motion of a displaced lipuid in a U-shaped tube is a S.H.M
It is a fact - by definition. You cannot prove it. You can verify it by comparing the two masses.
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A coordinate proof
Let G be the cyclic group generated by x, say. Ten every elt of G is of the form x^a, for some a
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you can coordinate parallel because parallel lines never touch or cross
There's a theorem to the effect that every group of prime order is cyclic. Since 5 is prime, the assertion in the question follows from the said theorem.
just count the squares and say there are an equal amount of squares?? if a line is bisecting the other line the dot is the midpoint
AEFD is a cyclic quad. Let angle EBC be x. Then EFC is 180-x, and EFD is x. We also know that BAD is 180- x ( cointerior angles). Hence BAD and EFD are supplementary. Use same technique, let angle BCF be y. Then you will get FDA to be supplementary to FEA. therefore aefd is a cyclic quad.
Lagrange theorem states that the order of any subgroup of a group G must divide order of the group G. If order p of the group G is prime the only divisors are 1 and p, therefore the only subgroups of G are {e} and G itself. Take any a not equal e. Then the set of all integer powers of a is by definition a cyclic subgroup of G, but the only subgroup of G with more then 1 element is G itself, therefore G is cyclic. QED.
By LaGrange's Thm., the order of an element of a group must divide the order of the group. Since 3 is prime, up to isomorphism, the only group of order three is {1,x,x^2} where x^3=1. Note that this is a finite cyclic group. Since all cyclic groups are abelian, because they can be modeled by addition mod an integer, the group of order 3 is abelian.
Step 1: Identify the coordinates of the vertices of the rhombus. Step 2: Calculate the coordinates of the midpoints of the sides. x-coordinate of midpoint = average of x-coordinates of the two end points, and similarly the y- coordinate. Step 3: Calculate lengths of sides of the quadrilateral formed (using Pythagoras) Step 4: Use step 3 results to show opposite sides are equal. Step 5: Calculate gradient (slope) of any two adjacent sides, if defined. Step 6: The two gradients multiply to -1 which shows that they are perpendicular. 4 and 6 prove that the quadrilateral is a rectangle. If a side of the quadrilateral is vertical, its gradient (step 5) is not defined, but then the adjacent side will be horizontal. And so the two sides are perpendicular.
no prove....