value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
You use Newton's Gravity Theory, GM/r = v^2. Then Earth mass M = rv^2/G = r^3w^2/G or M= r(2pi r)^2/GT^2
According to newtons formula; force F=G*m1*m2/(r^2) ,for 2 bodies facing each others gravitational pull When divided both sides by m1,so gravitational acceleration g=m2*g/(r^2) so g is directly proportional to mass of the body....
If Vo is the orbital velocity then the centrifugal force is m Vo2/ R+h where R is the radius of the earth and h is height of the body of mass m orbiting around the earth. The force of attraction between earth and body is G M m /(R+h)2 G is the universal gravitational constant and M is mass of the earth. For equilibrium the gravitational force will be equal to the centrifugal force. So Vo = sq root of GM/(R+h) But GM = gR2 g is acceleration due to gravity. So Vo = sq root of g R2/R+h When h is very much smaller compared to R then neglecting h we get Vo = sq root of gR So orbital velocity is directly proportional to the square root of acceleration due to gravity.
The only "strange marking" is the designer's monogram, a stylized G R, for Gilroy Roberts.
R. G. Armstrong was born on April 7, 1917.
R. G. Armstrong was born on April 7, 1917.
R. G. Armstrong was 95 years old when he died on July 27, 2012. (birthdate: April 7, 1917).
No one knows because they wernt with him that are still alive. And well r u him.
yes
yes
yes.
Yes
Still alive
Yes he is.
R.L. Stine, the author of the Goosebumps series, is still alive.
no i think he died in 1988