You get Iron (III) Hydroxide and Sodium Nitrate. It is a double displacement chemical reaction...
Aqueous sodium phosphate and aqueous iron nitrate react to produce aqueous sodium nitrate and solid iron phosphate.
no reaction
Iron Sulphate + Sodium Hydroxide -> Sodium Sulphate (Na2SO4) and Iron Hydroxide (Fe(OH)2)
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]
The formula for the compound Iron (II) Nitratrate (or Ferrous Nitrate) is Fe(NO3)2
Aqueous sodium phosphate and aqueous iron nitrate react to produce aqueous sodium nitrate and solid iron phosphate.
The iron(III) hydroxide is not soluble in water and doesn't react with sodium chloride.
no reaction
Any reaction occur.
Iron (II) chloride and sodium hydroxide react to produce iron (II) hydroxide and sodium chloride. FeCl2(aq) + NaOH(aq) --> Fe(OH)2(s) + NaCl(aq) This is a double replacement/displacement reaction.
Iron Sulphate + Sodium Hydroxide -> Sodium Sulphate (Na2SO4) and Iron Hydroxide (Fe(OH)2)
= iron hydroxide plus sodium chloride
FeSO4 + 2NaOH = Na2SO4(sodium sulphate] + Fe(OH)2 [iron(II) hydroxide / ferrous hydroxide].
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
Iron (II) nitrate and elemental copper.
Iron nitrate and metallic copper.
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]