The width of the room is equal to twice the Length. Suppose Length = L, width = W, and A = area
W = 2L from the information in the question
Now we know area, A is equal to length times width
W*L=A, plug in 2L for W and we get 2L*L=A or 2L^2=A
Next, we see that when 6 is subtracted from both length and width A becomes 108 less.
So (2L-6)*(L-6)=A-108
Multiply (2L-6)*(L-6) out and the result is (2L^2-18L+36) Set that equal to A-108
(2L^2-18L+36)=A-108. We found out that A=2L^2 earlier so we can substitute the terms.
(2L^2-18L+36)=2L^2-108. Now solve for L
Subtract 2L^2 from both sides
(-18L+36)=(-108)
Subtract 36 from both sides
(-18L)=(-144)
Divide by (-18)
L=8
We know W=2L so W=16
Now lets test our answer.
16*8=128
(16-6)*(8-6)=10*2=20
128-20=108
So the answer of L=8 and W=16 is correct.
15
28
lenght=15, width= 10
2,058/2,058= remander if 0 times 3 with the 0 and that will give you 0 and then you try to find the height of the length? The Answer is Fourteen or 14 cm for the height The Answer is twenty-one or 21 for the length
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
Twice the (width plus length)
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
2x-5 is twice a number decreased by 5.
Doubling the width of a rectangular rug will affect the perimeter because the total length and width will be doubled. The area will be twice the length times the width.
15
divide perimeter by 6.
28
The standard perimeter of a rectangular building can be found by adding the lengths of all four sides. It is twice the sum of the length and width of the building.
If one side is twice the length of the other and the square footage is 800 I'd say one side is 20 feet and the other is 40.
Perimeter of a rectanle is the sum of twice the length and twice thewidth. 140 + 140 + 2 x W = 410 2W = 410-280 = 130 W = width = 65 meters
Area=Length * Width. if length =4 and width =5...area is 20. if doubled....(4*2)*(5*2)=A*4. When length and width double, area is multiplied by 4.
Width = 16 feet Length = 38 feet