Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq).
An example is barium sulfate:BaCl2 + Na2SO4 = BaSO4 + 2 NaCl
Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq). The reaction results in the formation of insoluble barium sulfate (BaSO4).
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
Because Na2SO4 is an ionic compound and so does not have actual molecules.
Precipitation of barium sulfate:BaCl2 + Na2SO4 = BaSO4(s) + 2 NaCl
An example is barium sulfate:BaCl2 + Na2SO4 = BaSO4 + 2 NaCl
Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq). The reaction results in the formation of insoluble barium sulfate (BaSO4).
BaNo3+KSo4 BaNo3+KSo4
The carbon mineral bondinh
precipitation
solutions
Drought
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
Na2SO4(s) --> 2Na+(aq) + SO4-2(aq)
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O