0
Dan, den, din, don, dun
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
Word with 5 vowels?
Can it only consist of vowels? Many words have 5 vowels. Queueing has five in a row.
5 letter word starting with r without vowels?
all words have vowels in them
What is a 7 letter word with 2 vowels and 5 consonants with the letters G B D you G A B?
the sentence that you are asking is what rhymes with round? mound sound found clown these are the rhyming words. by caleb allen
Any 5 letter words ending in b with a vowels?
alibicombogumbomambojumbolimbomambamaybe
What rhymes with North America?
Northamerica rhymes with 2,999 known words and/or phrases available has 12 letters, 7 are consonants with 5 vowels. When pronounced, northamerica should have 5 syllables. An extensive rhyming dictionary for words that rhyme with northamerica!Unique Letters: a, c, e, h, i, m, n, o, r, t
What are some words that have all of the vowels?
Some words that have all 5 of the classic vowels are: sequoia education facetious authorize persuasion unreasoning Some that have all 5, and Y also, in order (AEIOUY) are abstemiously facetiously
What words contain all of the vowels?
Two words that contain all the English vowels (AEIOU and Y) are "facetiously" and "abstemiously" which even have them in order (also abstentiously). Other words are educationally and precariously. *For just the 5 standard vowels, see the related question below.
5 letter country words 2 vowels?
Sudan Japan China Ghana
How many vowels does louise have?
Four vowels.
5 v in the e a?
5 Vowels in the English Alphabet
A word with 2 vowels 5 consonants?
EthanCarlydiaryphonehouse
How many words with or without meaning each of 2 vowels and 3 consonants can be formed from the letters of the word DAUGHTER?
In the word DAUGHTER, there are 3 vowels namely, A, U, and E, and 5 consonants namely, D, G, H, T, and R. Number of ways of selecting 2 vowels out of 3 vowels = Number of ways of selecting 3 consonants out of 5 consonants = Therefore, number of combinations of 2 vowels and 3 consonants = 3 × 10 = 30 Each of these 30 combinations of 2 vowels and 3 consonants can be arranged among themselves in 5! ways. Hence, required number of different words = 30 × 5! = 3600
