not possible
The balanced chemical equation for the formation of rubidium hydroxide from rubidium oxide is: 2 Rb2O + 2 H2O → 4 RbOH
Rubidium metal would react with iodine to make rubidium iodide , according to the equation: 2 Ru + I2 -> 2 RuI
4
Rb(2)S(2)O(3) That's 2 atoms of Rubidium, 2 atoms of Sulfur, and 3 of Oxygen.
37
what is the balanced equation for Rubidium metal reacting with halogen iodine
2
2+2=4.
Nitrogen Is Uncreative beacuase of the triple bond between 2 nitrogen atom,which have a bond enthalpy of 945kjmol-1,and this result for a fewer reactions of nitrogen.
It's just Rubidium Sulfate. The name rubidium sulfate (sulfate is SO3)assumes that people can figure out the chemical formula based on the oxidation numbers of rubidium (+1) and sulfate (-2) and crisscrossing to get a net oxidation number of zero.
Rubidium (Rb) can react with many things such as hydrogen because rubidium has one spare electron 2, 8, 18, 8, 1 and hydrogen has only one outer electron so hydrogen in water will reactvigorously with rubidium as hydrogen is desperate to gain one electron and rubidium is desperate to lose one electron and when these bond they form an ion.
2 NH3 + 3 O2 = N2O3 + 3H2O