not possible
The reaction of rubidium (Rb) with nitrogen gas (N₂) primarily produces rubidium nitride (Rb₃N). In this reaction, three moles of rubidium combine with one mole of nitrogen to form one mole of rubidium nitride. The overall balanced equation for this reaction is: 3 Rb + N₂ → Rb₃N.
The balanced chemical equation for the formation of rubidium hydroxide from rubidium oxide is: 2 Rb2O + 2 H2O → 4 RbOH
Rubidium metal would react with iodine to make rubidium iodide , according to the equation: 2 Ru + I2 -> 2 RuI
4
Rb(2)S(2)O(3) That's 2 atoms of Rubidium, 2 atoms of Sulfur, and 3 of Oxygen.
what is the balanced equation for Rubidium metal reacting with halogen iodine
37
2
2+2=4.
Rubidium (Rb) can react with many things such as hydrogen because rubidium has one spare electron 2, 8, 18, 8, 1 and hydrogen has only one outer electron so hydrogen in water will reactvigorously with rubidium as hydrogen is desperate to gain one electron and rubidium is desperate to lose one electron and when these bond they form an ion.
It's just Rubidium Sulfate. The name rubidium sulfate (sulfate is SO3)assumes that people can figure out the chemical formula based on the oxidation numbers of rubidium (+1) and sulfate (-2) and crisscrossing to get a net oxidation number of zero.
Nitrogen Is Uncreative beacuase of the triple bond between 2 nitrogen atom,which have a bond enthalpy of 945kjmol-1,and this result for a fewer reactions of nitrogen.