The matrix is singular because the last equation is the same as the second equation (simply multiplying every term in an equation by the same number (in this case, 2) does not produce an equation with new information).
for example
1) 3x=3y
2) 2x=2y
has no useful solution beyond the information from 1) that x=y
You would get a singular matrix for this.
The Gauss-Jordan method will not solve equations which cannot be solved by the old "elimination method".
r=0 is the solution...
The equation is [ 5y = 35 ].The solution to the equation is [ y = 7 ].
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
root
one
y = -2.5 is a equation. And solution to the equation is finding the value of the variable. If we see the equation y is already equal to -2.5 which is the solution to the equation.
r=0 is the solution...
An equation never equals a number, but its solution often does.-- An equation with a solution of six: [ 3x - 14 = 4 ]-- An equation with a solution of three: [ 14 - 10x = -16 ]-- An equation with both solutions: [ x2 - 9x + 20 = 2 ]An equation that equals 6 is 10 - 4 = 6An equation that equals 3 is 10 - 7 = 3
The equation is [ 5y = 35 ].The solution to the equation is [ y = 7 ].
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
one
Possibly the solution to an equation
root
No.
It has one real solution.
That's an invalid equation.
w=4.5