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What are the ideal op-amp approximations?
Ideal op amp approximations: -no current goes into the positive or negative input of the op amp. -The open loop gain is infinite. -Voltage at positive input is the same as the negative input.
What is an Ideal Op Amp?
One that is not affected by noise and doesn't vary.
How gain varies with bandwidth in an op-amp?
The gain of an op amp varies with frequency. After an op amp reaches the half-power point, the gain falls appreciably. And then once it hits the transition frequency, the op amp no longer provides any gain.
Why open loop gain of op-amp is very high?
A; An ideal op amp should have infinite open loop gain so when the loop is closed with negative feedback it will be stable
What is loading effect of op amp?
An 'ideal' op-amp has infinite input impedance, and real ones that you can buy for anickel come pretty close. That means that the input impedance or "loading effect" ofan op-amp all by itself is nearly zero, and the loading effect of a circuit that youbuild with an op-amp is completely determined by the components you choose toconnect to it. You design the circuit to load the previous stage in any way you want.
What is vcc and -vee in opamp?
In an operational amplifier (op-amp), Vcc and Vee refer to the power supply voltages that provide the necessary electrical energy for the op-amp to function. Vcc typically represents the positive supply voltage, while Vee represents the negative supply voltage. These voltages determine the output voltage range of the op-amp and are essential for defining the op-amp's operating conditions. Properly selecting and connecting these power supplies is crucial for optimal op-amp performance.
Why clipping happen for op-amp?
Clipping occurs in the voltage waveform when the input voltage, multiplied by the voltage gain of the op-amp circuit, exceeds the op-amp supply voltage as limited by the output network. The supply voltage and output network, limits the maximum voltage that can be achieved at the output. The op-amp behaves normally within its range of maximum voltage output, and then it is clipped when it reaches the maximum voltage of the circuit.
If an op-amp were perfect the CMRR would be what?
If an operational amplifier (op-amp) were perfect, the Common Mode Rejection Ratio (CMRR) would be infinite. This is because a perfect op-amp would completely reject any common-mode signals while amplifying differential signals without any error. In reality, op-amps have limitations that result in finite CMRR values, but the ideal scenario assumes perfect behavior.
What happens when magnitude of Vcc and Vee of op-amp are different?
When the magnitude of Vcc and Vee of op-amp are different the op-amp produces waveforms equal in the size of each rail.
How an op amp differs from a basic amp?
A basic, single transistor amplifier differs from an op amp: 1. The op amp has more gain 2. The op amp may have higher input resistance (so it loads the circuit less) 3. The op amp may have a lower output resistance (so it can drive larger currents) 4. The op amp likely has a lower frequency response (due to the high gain, unless you provide some sort of feedback loop) 5. The op amp is ridiculously complex compared to a simple amplifier 6. The op amp will require a positive and negative voltage (may be unnecessary with a single transistor amplifier)
Distinguish between op amp and differential amplifier?
Look up "op amp" on wikipedia, there is a good drawing near the bottom right. An op amp contains a differential amplifier as the first stage, but has multiple following stages that provide amplifier near ideal characteristics of high input resistance and low output resistance (it can drive more current than a single dif amplifier stage).
Which characteristics of Op-Amp is responsible for virtual ground?
The main parameter responsible for virtual ground of an Op-Amp is Input Impedance . Generally , for an Op-Amp it is very high . So , we can conclude that the characteristics of an Op-Amp responsible for virtual ground is high input impedance .
