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Q: Starting from rest a ball rolls down a long incline with a constant acceleration After 2 seconds it traveled 2 meters In the next second it will have travled?
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Why is the ball deccelerating on an inclined plane?

The acceleration due to gravity remains constant, regardless of incline. The fact that it is on an incline does not change the fact that it will remain constant, it will only change the component of that acceleration being applied to the ball.


If mass increases and there is no friction would the acceleration of an object increase when place on an incline plane?

Yes. The acceleration is directly proportional to the objects mass.For objects with constant mass however, the acceleration will remain constant.


Which will have the greater acceleration rolling down an incline plane a large ball or a small ball?

If they are both solid, and the incline is the same, the rate of acceleration will be the same.


Which will have the greater acceleration rolling down an incline plane- a large ball or a small ball?

If they are both solid, and the incline is the same, the rate of acceleration will be the same.


What is the nature of distance time graph for the motion of an object moving with a changing speed?

An incline represents acceleration, a straight line represents a constant speed and a decline represents slowing down.


Why does the acceleration of an object rolled down an incline increase as the angle of incline increases?

The contribution of the acceleration of gravity in the direction of motion increases as the angle of the incline increases. Or in other words, as the angle between the direction of motion and the force of gravity goes to zero, the acceleration of the object goes to the gravitational acceleration. a = g cos(theta) Where theta is the angle between the direction of motion and verticle, which is in fact (theta = 90 - angle of the incline)Where a is the acceleration of the object down the incline plane and g is the acceleration due to gravity. Theta is the angle between the direction of motion of the accelerating object and the acceleration of gravity. Initially, the angle between a and g is 90 degrees (no incline) and therefore g contributes nothing to the objects acceleration. a = g cos(90) = 0 As the angle of the inclined is increased, the angle between a and g approaches zero, at which point a = g. With no other forces acting upon the object, g is its maximum acceleration.


How do you measure the acceleration of a moving object of an object at an incline?

with a speed gun


How would the observed value of the acceleration of a block be affected if the one used is heavier?

From f = m*a, a = f/m, so if the force remains constant and the mass increases, the acceleration will decrease. But if the block is on an incline and the force is provided by gravity, the force will increase directly proportional to the mass of the block, and acceleration will remain the same.


Discuss the validity of extrapolating the acceleration value to an angle of 90?

Extrapolate the experimental values of acceleration, vs. angle of the incline, to find the acceleration when the angle of inclination = 90 degrees. The acceleration at 90 degrees will equal 9.81 m/s/s, since this is the free-fall acceleration.


Why does a toy car rolling at constant speed down a straight incline track slow down when reaching the base of the incline?

i think this happens due to friction between the ground and the toy car :)


Are you agree that your weight is equivalent to the friction force. Why?

No. On a horizontal surface the normal force is equal to weight. If you are moving at constant velocity you only overcome frictional force, which is not equal to weight. This is easier to see on an incline. At some point an object will slide at constant velocity down the incline. This is related to trig functions of the angle of incline multiplied by the weight which is always less than the weight.


Predict the effect that significant friction would have on the acceleration of the box as it slides down the incline. Explain the cause of the predicted effect?

I have no clue.