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Yes. The acceleration is directly proportional to the objects mass.For objects with constant mass however, the acceleration will remain constant.
If they are both solid, and the incline is the same, the rate of acceleration will be the same.
with a speed gun
From f = m*a, a = f/m, so if the force remains constant and the mass increases, the acceleration will decrease. But if the block is on an incline and the force is provided by gravity, the force will increase directly proportional to the mass of the block, and acceleration will remain the same.
i think this happens due to friction between the ground and the toy car :)
The acceleration due to gravity remains constant, regardless of incline. The fact that it is on an incline does not change the fact that it will remain constant, it will only change the component of that acceleration being applied to the ball.
Yes. The acceleration is directly proportional to the objects mass.For objects with constant mass however, the acceleration will remain constant.
If they are both solid, and the incline is the same, the rate of acceleration will be the same.
If they are both solid, and the incline is the same, the rate of acceleration will be the same.
An incline represents acceleration, a straight line represents a constant speed and a decline represents slowing down.
The contribution of the acceleration of gravity in the direction of motion increases as the angle of the incline increases. Or in other words, as the angle between the direction of motion and the force of gravity goes to zero, the acceleration of the object goes to the gravitational acceleration. a = g cos(theta) Where theta is the angle between the direction of motion and verticle, which is in fact (theta = 90 - angle of the incline)Where a is the acceleration of the object down the incline plane and g is the acceleration due to gravity. Theta is the angle between the direction of motion of the accelerating object and the acceleration of gravity. Initially, the angle between a and g is 90 degrees (no incline) and therefore g contributes nothing to the objects acceleration. a = g cos(90) = 0 As the angle of the inclined is increased, the angle between a and g approaches zero, at which point a = g. With no other forces acting upon the object, g is its maximum acceleration.
with a speed gun
From f = m*a, a = f/m, so if the force remains constant and the mass increases, the acceleration will decrease. But if the block is on an incline and the force is provided by gravity, the force will increase directly proportional to the mass of the block, and acceleration will remain the same.
Extrapolate the experimental values of acceleration, vs. angle of the incline, to find the acceleration when the angle of inclination = 90 degrees. The acceleration at 90 degrees will equal 9.81 m/s/s, since this is the free-fall acceleration.
i think this happens due to friction between the ground and the toy car :)
No. On a horizontal surface the normal force is equal to weight. If you are moving at constant velocity you only overcome frictional force, which is not equal to weight. This is easier to see on an incline. At some point an object will slide at constant velocity down the incline. This is related to trig functions of the angle of incline multiplied by the weight which is always less than the weight.
I have no clue.