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How many grams of oxygen are needed to react with 215g of hydrazine in the equation N2H2 plus 3O2 to yield 2NO2 plus 2H2O?
Using the stoichiometry of the equation, for every 1 mole of N2H2, 3 moles of O2 are needed. The molar mass of N2H2 is 32 g/mol and O2 is 32 g/mol. First, calculate the moles of N2H2 from 215g, then use the mole ratio to find the moles of O2 needed, and finally convert that to grams.
For the following equation SnO2 plus 2H2 equals Sn plus 2H20 how many grams of Sn is formed if 12.5 grams of the first reactant is used?
To find the grams of Sn formed, we first need to calculate the number of moles of SnO2 in 12.5 grams. Then, we use the stoichiometry of the reaction to relate the number of moles of SnO2 to the number of moles of Sn. Finally, we convert the moles of Sn to grams using the molar mass of Sn.
Use the following balance equation to answer this question n2h4 plus 2h2o2 -- n2 plus 4h2o How many grams of h2o are produced from 27 grams of n2h4?
First, calculate the molar mass of N2H4 (hydrazine) to be 32 g/mol. Use the stoichiometry of the balanced equation to find the molar ratio of N2H4 to H2O, which is 1:4. Next, determine the number of moles of N2H4 in 27 grams and then use the molar ratio to find the number of moles of H2O produced. Finally, convert the moles of H2O to grams using the molar mass of H2O (18 g/mol).
NiCO3 plus H2SO4 NiSO4 plus Co2 plus H2O How many grams of nickel Carbonate are needed to react with 12 grams of sulfuric acid?
To determine how many grams of nickel carbonate (NiCO₃) are needed to react with 12 grams of sulfuric acid (H₂SO₄), we first need to know the molar masses: NiCO₃ (approximately 118.7 g/mol) and H₂SO₄ (approximately 98.1 g/mol). The balanced chemical equation indicates a 1:1 molar ratio between NiCO₃ and H₂SO₄. Calculating the moles of H₂SO₄ in 12 grams gives us about 0.122 moles. Thus, we will need an equal amount of moles of NiCO₃, which corresponds to about 14.5 grams of NiCO₃ (0.122 moles × 118.7 g/mol).
Consider the following balanced chemical reaction 2 C2H4O plus 5 O2 ---------- 4 CO2 plus 4 H2O How many grams of O2 are required to produce 20.0 g of CO2?
10,225 g oxygen are required.
How many grams of oxygen are needed to react with 215g of hydrazine in the equation N2H2 plus 3O2 to yield 2NO2 plus 2H2O?
Using the stoichiometry of the equation, for every 1 mole of N2H2, 3 moles of O2 are needed. The molar mass of N2H2 is 32 g/mol and O2 is 32 g/mol. First, calculate the moles of N2H2 from 215g, then use the mole ratio to find the moles of O2 needed, and finally convert that to grams.
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
What is mass of calcium carbonate is to be decomposed to obtain 4.4 gram of carbon dioxide in the reaction caco3-cao plus o2?
The equation given shows that each formula mass of calcium carbonate produces one formula mass of CO2. The gram formula masses of calcium carbonate and carbon dioxide are 100.09 and 44.01 respectively. Therefore, to produce 4.4 grams of carbon dioxide, 4.4(100.09/44.01), or 10 grams of calcium carbonate, to the justified number of significant digits, are needed.
How many grams of 2na plus cL2 would be required to produce 4 grams of table salt?
To produce 4 grams of table salt (NaCl), you would need 2 moles of Na and 1 mole of Cl2. This corresponds to 46 grams of Na and 71 grams of Cl2. This would total 117 grams of reactants (2Na + Cl2) to produce 4 grams of NaCl.
For the following equation SnO2 plus 2H2 equals Sn plus 2H20 how many grams of Sn is formed if 12.5 grams of the first reactant is used?
To find the grams of Sn formed, we first need to calculate the number of moles of SnO2 in 12.5 grams. Then, we use the stoichiometry of the reaction to relate the number of moles of SnO2 to the number of moles of Sn. Finally, we convert the moles of Sn to grams using the molar mass of Sn.
What is 150.0000 grams plus 0.3 mg?
150.0000 grams plus 0.3 milligrams = 150.0003 grams
How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.690 g of Fe2S3 if the percent yield for the reaction is 65.0 3 Na2S(aq) plus 2 FeCl3(aq) Fe2S3(s) plus?
To find the moles of Fe2S3 produced, convert 0.690 g to moles using the molar mass of Fe2S3. Then, use the stoichiometry of the reaction to determine the moles of FeCl3 required. Finally, use the molarity of FeCl3 to calculate the volume in milliliters needed, keeping in mind the percent yield.
6 grams plus 3 kg equal how many grams?
6 grams plus 3 kilograms equals 3,006 grams
Use the following balance equation to answer this question n2h4 plus 2h2o2 -- n2 plus 4h2o How many grams of h2o are produced from 27 grams of n2h4?
First, calculate the molar mass of N2H4 (hydrazine) to be 32 g/mol. Use the stoichiometry of the balanced equation to find the molar ratio of N2H4 to H2O, which is 1:4. Next, determine the number of moles of N2H4 in 27 grams and then use the molar ratio to find the number of moles of H2O produced. Finally, convert the moles of H2O to grams using the molar mass of H2O (18 g/mol).
What does 63.25 grams plus 194.6 grams equal to?
257.85 grams
How many is 2.2 kg plus 700 grams plus 250 grams?
2.2kg is 2200 grams. 2200 + 700 + 250 = 3150 grams.3150 grams is 3.15 kg.
What does 2 kg plus 570 grams equal?
2 kg plus 570 grams = 2.57 kg or 2570 grams
