Using the stoichiometry of the equation, for every 1 mole of N2H2, 3 moles of O2 are needed. The molar mass of N2H2 is 32 g/mol and O2 is 32 g/mol. First, calculate the moles of N2H2 from 215g, then use the mole ratio to find the moles of O2 needed, and finally convert that to grams.
According to the Wikipedia article on hydrazine, the molecular formula for hydrazine is N2H4 and it's molar mass is 32.0452g/mol.1 mole N2H4 = 32.0452g/mol = 6.022 x 1023moleculesConvert mass in grams to moles.10.11g hydrazine x 1mol/32.0452g = 0.3155mol hydrazineConvert moles to molecules.0.3155mol hydrazine x 6.022 x 1023molecules/mol = 1.900 x 1023molecules hydrazine
800 g oxygen are needed.
128 g of oxygen are needed.
To determine the grams of glucose formed, we can use the balanced equation for photosynthesis: 6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂. From the equation, 6 grams of carbon dioxide and 6 grams of water produce 1 gram of glucose and 6 grams of oxygen. Given that 16 grams of oxygen are produced, that corresponds to 16 grams of O₂, which comes from 6 grams of CO₂ and 6 grams of H₂O multiple times. Thus, when 22 grams of CO₂ and 9 grams of H₂O are used, we can find that glucose produced is 6.67 grams.
To calculate the grams of CO needed to react with Fe2O3, you need to write a balanced chemical equation for the reaction, determine the moles of Fe2O3 given the mass provided, and use the stoichiometry of the balanced equation to find the moles of CO needed. Finally, convert the moles of CO to grams using the molar mass of CO.
To determine the grams of hydrazine (N2H4) needed to produce 96.0 grams of water (H2O), we start with the balanced chemical equation for the reaction: 2 N2H4 + 2 O2 → 4 H2O + N2. From this equation, we see that 2 moles of hydrazine produce 4 moles of water. The molar mass of water is approximately 18 g/mol, so 96.0 g of water corresponds to 5.33 moles of water. This means 2.67 moles of hydrazine are required, which equals about 66.3 grams of hydrazine (with a molar mass of 32.05 g/mol).
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
To find the grams of oxygen needed, we first calculate the molar mass of titanium chloride (TiCl4) and oxygen (O2). Then, we use the molar ratio of TiCl4 to O2 from the balanced chemical equation to find the grams of O2 needed.
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
The variables for the formula are incomplete. You would need to know how many grams of butane are put out by the lighter. The molecular weight of butane is 58.12 g/mol, which is also needed to complete the formula.
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
To calculate the grams of oxygen needed, you first need to balance the chemical equation for the combustion of butane. C₄H₁₀ + O₂ → CO₂ + H₂O. From the balanced equation, 2 moles of butane react with 13 moles of oxygen. One mole of butane is 58.12 g, and one mole of oxygen is 32 g. Therefore, 5.0 g of butane would require (5.0 g / 58.12 g/mol) * 13 moles of oxygen, which is approximately 1.12 grams of oxygen.
To determine the amount of gas needed to react with 348.5 grams of oxygen, you need to know the balanced chemical equation of the reaction. Then, use the stoichiometry of the reaction to calculate the amount of gas required based on the molar ratio between the gas and oxygen in the reaction.
According to the Wikipedia article on hydrazine, the molecular formula for hydrazine is N2H4 and it's molar mass is 32.0452g/mol.1 mole N2H4 = 32.0452g/mol = 6.022 x 1023moleculesConvert mass in grams to moles.10.11g hydrazine x 1mol/32.0452g = 0.3155mol hydrazineConvert moles to molecules.0.3155mol hydrazine x 6.022 x 1023molecules/mol = 1.900 x 1023molecules hydrazine
The balanced chemical equation for the reaction of ethanol with oxygen to form carbon dioxide and water is C2H5OH + 3O2 -> 2CO2 + 3H2O. From this equation, we can see that 3 moles of oxygen are needed to react with 1 mole of ethanol. Therefore, 2 moles of ethanol will require 6 moles of oxygen to react. To find the grams of oxygen, you can multiply the moles of oxygen by its molar mass (32 g/mol).
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?