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To form iron(III) oxide, the chemical equation is:

4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)

From the equation, it can be seen that 3 moles of oxygen (O2) are needed to react with 4 moles of iron (Fe) to produce 2 moles of iron(III) oxide (Fe2O3). The molar mass of oxygen (O2) is approximately 32 g/mol. Therefore, you would need 96 grams of oxygen to react with the iron needed to form iron(III) oxide.

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How many grams of iron will be needed to react completely with an excess of oxygen to form 40 grams of iron3 oxide?

To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.


When 31 grams of phosphorous reacts with oxygen 71 grams of an oxide phosphorus is the product. What mass of oxygen is needed to produce 13 grams of this product?

To find the mass of oxygen needed to produce 13 grams of the oxide, we first find the molar ratio between P and O in the product. Then, use this ratio to calculate the mass of oxygen needed. Since 71g of the oxide contains 31g of phosphorus, we can calculate the mass of oxygen needed for 13g of the oxide by setting up a proportion.


How many grams of mercury II oxide are needed to produce 1.56 L of oxygen gas according to the following reaction at 25C and 1 ATM?

You would need 5.7 grams of mercury II oxide to produce 1.56 L of oxygen gas according to the following reaction at those conditions.


If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?

To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.


How many grams of magnesium oxide and oxygen react to form 20.0 grams of magnesium oxide?

To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.

Related Questions

How many grams of iron will be needed to react completely with an excess of oxygen to form 40 grams of iron3 oxide?

To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.


When 31 grams of phosphorous reacts with oxygen 71 grams of an oxide phosphorus is the product. What mass of oxygen is needed to produce 13 grams of this product?

To find the mass of oxygen needed to produce 13 grams of the oxide, we first find the molar ratio between P and O in the product. Then, use this ratio to calculate the mass of oxygen needed. Since 71g of the oxide contains 31g of phosphorus, we can calculate the mass of oxygen needed for 13g of the oxide by setting up a proportion.


There are 6 grams of magnesium and 4 grams of oxygen if 8 grams of magnesium oxide is produced?

2


How many grams of mercury II oxide are needed to produce 1.56 L of oxygen gas according to the following reaction at 25C and 1 ATM?

You would need 5.7 grams of mercury II oxide to produce 1.56 L of oxygen gas according to the following reaction at those conditions.


If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?

To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.


There are 3 grams of magnesium and 2 grams of oxygen if 4 grams of magnesium oxide is produced and all of the magnesium was used up how many grams of oxygen are left?

If 3 grams of magnesium are used to form 4 grams of magnesium oxide, then 1 gram of oxygen is used in the reaction. This means 1 gram of oxygen remains unused.


How many grams of magnesium oxide and oxygen react to form 20.0 grams of magnesium oxide?

To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.


How many grams of oxygen gas are required to react completely with 14.6 grams of solid sodium to form sodium oxide?

Balanced equation. 4Na + O2 ->2Na2O 14.6 grams Na (1 mole Na/22.99 grams)(1 mole O2/4 mole Na)(32.0 grams/1 mole O2) = 5.08 grams oxygen gas needed --------------------------------------------


What does 'oxide mean' in the word magnesium oxide?

same thing as oxygen no subscripts needed


How many grams of oxygen are needed to produce 95.6 g of aluminum oxide?

To find the amount of oxygen needed to produce 95.6 g of aluminum oxide (Al2O3), first calculate the molar mass of Al2O3 (101.96 g/mol). Then, set up a ratio using the molar mass ratio of oxygen to Al2O3 (3:2). Calculate the amount of oxygen needed using the given mass of Al2O3 and the molar ratio.


What weight of oxygen will react with 40 gram of ca?

For every 40 grams of calcium (Ca), 32 grams of oxygen (O) will be needed to react. This is based on the chemical formula for calcium oxide (CaO), where one calcium atom reacts with one oxygen atom to form one molecule of CaO.


Which elements is needed to create nitrous oxide?

Nitrogen and Oxygen