It doesn't. Going up it has the acceleration from the kick minus acceleration due to gravity. Going down it just has acceleration due to gravity. I suppose it could be the same if the former equaled 9.8 m/s
The initial acceleration of an object can be found by calculating the change in velocity over time. This can be done by dividing the final velocity by the time taken to reach that velocity. The formula for initial acceleration is: initial acceleration = (final velocity - initial velocity) / time.
F=mass * acceleration 60kg m/s^2=10kg * acceleration 6m/s^2 = acceleration
The object's instantaneous acceleration is (8t - 8) at any time.We can't calculate the average acceleration, because you haven't defined a periodof time over which to average it. We need the start and finish times in order tofind an average.
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
If speed does not change, then acceleration is 0 To find acceleration, you must also know the time Speed = metres per second. Acceleration = meters per second, per second Therefore you can use the equation m/s2 to find the acceleration. change in speed/ change in time.
In case of uniform acceleration,the graph will be a straight line with a +ve slope ,if we are taking velocity along Y-axis and time along X-axis.hence it's slope will give u acceleration.
Deceleration- the opposite of acceleration.
Cleavage
Actually, objects moving around a circular path have two accelerations i.e. radial acceleration and tangential acceleration. Radial acceleration is towards the radius whereas tangential acceleration is the acceleration along the direction of the tangent to the path of the motion. So, I would say yes, they are accelerated towards the outer edge of the circle.
cleavage
Cleavage
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