If the inequality is strict (< or >) then the boundary is not included. Otherwise (≤ or ≥), it is.
Substitute the number in place of the variable, and see whether the inequality is then a true statement.
If the inequality is > (greater than) or >= (greater than or equal to), then there are an infinite number of solutions. So let the inequality be < (less than) or <= (less than or equal to) x = 1: 5y <= 16 so y = 1, 2 or 3 x = 2: 5y <= 12 so y = 1 or 2 x = 3: 5y <= 8 so y = 1 x >= 4: 5y <= 4 no solution. So whether the inequality is < or <= there are 6 ordered pairs.
A parenthesis is used for a number which is an 'end' of an inequality but is not itself included. For example, if the inequality reads "x>3", there is an opening parenthesis on the hash-mark labelled '3', and the number line is shaded to the right. If the number IS included a bracket is used. So for -3 is less than or equal to x but less than 3, there is a [ on -3, and a ) on the 3, and the number line is shaded between -3 and 3.
A dashed line is used when the equality is equal to and less than/more than. (≤, ≥) A solid line is used when the inequality is just less than/more than. (<, >)
It depends upon whether the inequality is strictly less than (<), or if it is less than or could be equal (≤). For example: if x < 6, x can have any value less than 6, but cannot have the value 6; but if x ≤ 6, x can have any value less than 6, but can also have the value 6. Or put another way, x = 6 is NOT a solution of x < 6, but IS a solution to x ≤ 6.
Substitute the number in place of 'x' in the inequality, and see whether the statement you have then is true.
Substitute the number in place of the variable, and see whether the inequality is then a true statement.
That will all depend on what the question was!
The answer depends on the nature of the inequality: whether it is linear, quadratic or has some other functional form.
Whether inequality exist
If the inequality is > or< then it is an open circle. If it is greater than or equal to or less than or equal to, it is a closed circle.
I don't see any numbers below.One method to solve this is to replace each of the numbers in the inequality, do the calculations, and then check whether the inequality is satisfied. Another method is to get the general solution for the inequality, then check with each of the numbers.
The slope-intercept inequality is an equation of the form y < mx + c. The inequality can be reversed, and in both cases can be strict or not. In all cases the equality divides the Cartesian plane into two and the inequality determines which side of the straight line is the valid region, and whether or not the line itself should be included.
Good question.Think about lxl > 3: x can be >3 or goes with or. < goes with and.
That's not an inequality; an inequality needs a "greater than" or a "less than" sign. Those must have gotten lost when you typed the title. Anyway, basically you are supposed to replace the numbers one by one in the inequality, do the calculations, and see whether the resulting statement is true or not.
whether or not you are still married i suppose.
Use the quadratic formula for the equality. Then, depending on the coefficient of x2 and the nature of the inequality [>, ≥, ≤, <], determine whether you need the open or closed intervals between the roots or beyond the roots.