answersLogoWhite

0

YourType *p;

p = (YourType *)calloc (no_of_elements, sizeof (YourType));

if (p==NULL) {

fprintf (stderr, "Out of memory\n");

exit (32);

}

User Avatar

Wiki User

14y ago

What else can I help you with?

Related Questions

What is really meant by malloc and where you will use this malloc?

malloc is a function of the standard c library (stdlib) and it is abbreviation for memory allocate. What this function does is allocates memory in the RAM of computer to store variable data in it. You will use it whenever you need a place to store you temporary data such as an array or structure. To use malloc all you have to do is call malloc and tell it the size of the memory you want. It will then return a pointer to that memory. persumabely if it fails it returns NULL.


How do you use 2-D array with malloc?

You use a 2-D array with malloc the same way you use any other structure or scalar with malloc. The malloc library call takes a single argument of type size_t (in bytes) and returns a void* pointer to a region of memory that is suitably aligned for any supported data type. An example using the 2-D array... int *myArray[10][20]; myArray = malloc (sizeof (myArray)); if (myArray == NULL) {...exception processing...}; Note that a 2-D array is really the same as a 1-D array - its a linear region of memory - its just that the compiler does address arithmetic for you.


What is a malloc function in C programming with example?

The malloc() function is part of a class of functions that deal with the allocation of memory on the heap. int *a = malloc (sizeof (int) * 100); /* allocate 100 int's */ if (a == NULL) {...} /* deal with possible malloc failure */ /* use a, either as pointer or as array of 100 ints */ free (a); /* release memory back to the library */


What is malloc function in C?

The malloc function is a function used in C/C++ and various other high-level programming languges to add memory to the heap, it is essentially a pointer int* X = malloc(sizeof(int)); Where the parameter to malloc is the number of bytes you want to make room for. Because we are using an integral variable we want to make as much room as an integer takes.


How do you use dynamic memory allocation in getting a array?

Its simple void main() { int *arr[10]; arr=(int*)malloc(sizeof(int)*10); ...... ...... ...... ...... free(arr); }


What is the difference between Malloc and calloc in C and JAVA?

In C, malloc is used to reserve a predetermined size of memory. void * malloc ( size_t size ); calloc is used to reserve a chunk of memory large enough to store num elements, each of a predetermined size. void * calloc ( size_t num, size_t size ); To create a char array of size 10 you can do it in one of two ways: char* mChars = malloc( 10 * sizeof(char) ); char* cChars = calloc( 10, sizeof(char) ); There is no concept of malloc or calloc in Java.


How do you declare an N-Dimensional array using Malloc?

#include <stdlib.h> int **array1 = malloc(nrows * sizeof(int *)); for(i = 0; i < nrows; i++) array1[i] = malloc(ncolumns * sizeof(int));


Can arrays be created dynamically?

Yes, arrays can be created dynamically. The following shows how it can be done in C: void f (unsigned n) { int* p = malloc (n * sizeof (int)); /* allocate memory to accommodate n integers */ /* use p... */ free (p); p = 0; }


What is array Explain with syntax?

an array is a collection of the same data type.


How do you locate memory in array?

The array name is a reference to the start address of the array, so simply take its address. int a[10]; int* p1 = &a; If the array is allocated on the heap, then there is no name (all allocations on the heap are anonymous). However, you don't need a name since you already know the address: int* p2 = malloc (10 * sizeof (int));


What is the syntax for determining the size of an array in C using the keyword sizeof?

To determine the size of an array in C using the keyword sizeof, you would use the syntax: sizeof(array) / sizeof(array0).


Calloc allocates a block of memory for an array of elements of a certain size?

No. The calloc function allocates a block of memory for a count of a specific type. The size of the type is already known to the compiler so does not need to be specified, it will automatically multiply the type's size by the count. With malloc, you have to allocate memory in bytes, therefore you need to calculate exactly how many bytes you will need for a given type and the number of elements of that type. Examples (allocate 100 integers): int* p = (int*) malloc (sizeof (int) * 100); int* q = (int*) calloc (int, 100); Note also that malloc does not initialise the memory whereas calloc does (the allocated memory is initialised with the value zero). As such, malloc is more efficient when you want to initialise the memory by copying from other memory. That is, there's no point initialising memory you're going to initialise manually, so long as you don't access that memory before it is initialised.