The gram molecular mass of glucose is 180 gram. Reason. The atomicity of glucose is 24.
To determine the amount of glucose needed to produce 500g of ethyl alcohol, we need to calculate the molecular weight of ethyl alcohol (C2H5OH) and the molar ratios based on the given equation. The molecular weight of ethyl alcohol is 46g/mol. From the equation, for every 1 mole of glucose (180g/mol) consumed, 2 moles of ethanol are produced. Therefore, to produce 500g of ethanol, you would need to use 180g (1 mole) of glucose.
One mole of a substance is always 6.02X10^23 , since 180g of Glucose is one mole, therefore one mole of Glucose (180g) has 6.02X10^23 Molecules (particles) Avogadros' Number.
Glucose has a molar mass of 180g/mol, and we arrive at this figure by adding up the atomic masses of all its constituent atoms. Carbon accounts for 72 of these 180g (12x6), so 72/180 = 0.4, which is 40%.
5/9 of 180g is 100g
180g is 0.18 kilograms.
To calculate the mole fraction of glucose, first find the moles of each component by dividing its mass by its molar mass. The molar mass of glucose (C6H12O6) is 180 g/mol. The moles of glucose is 180g / 180 g/mol = 1 mol. The moles of water is 162g / 18 g/mol = 9 mol. The total moles in the solution is 1 + 9 = 10 mol. The mole fraction of glucose is 1 mol / 10 mol = 0.1.
2 moles in 2 liters means 1 mole in 1 liter - so it its molarity is 1.
40% of 180g= 40% * 180= 0.4 * 180= 72g
The boiling point of a solution can vary depending on the concentration of solute. For a dilute solution of glucose in water, the boiling point elevation is typically small and may not be easily measurable. However, pure glucose itself does not have a defined boiling point as it decomposes upon heating.
180g = 0.18kg
180g = 6.35oz
820g