the answer is that c is double the value of b
One half?
It means that if you substitute b for a, c for b and a for c the value of the determinant remains unchanged.It means that if you substitute b for a, c for b and a for c the value of the determinant remains unchanged.It means that if you substitute b for a, c for b and a for c the value of the determinant remains unchanged.It means that if you substitute b for a, c for b and a for c the value of the determinant remains unchanged.
Half of B refers to dividing the value of B by two. If B represents a numerical value, then half of B is mathematically expressed as B/2. For example, if B is 10, then half of B would be 5.
The expression 2b - c represents the result of subtracting the value of c from twice the value of b. This can also be written as 2 multiplied by the variable b, then subtracting the value of c. The result will depend on the specific values of b and c.
B sharp on the piano is C because C is one half step after B :-)
A B sharp is actually a C, and it's a half step up from B and a half step down from C sharp. So basically its between B natural and C sharp.
# include<stdio.h> main() { int a,b,c; print f("enter the values of a,b,c"); scan f("%d%d%d",&a,&b,&c); if((a>b)&&(a>c)) print f("Greatest value is a =%d",a); else if((b>a)&&(b>c)) print f("Greatest value is b=%d",b); else print f("Greatest value is c=%d",c); }
dim a,b,c a=cint(inputbox("enter value for a")) b=cint(inputbox("enter value for b")) c=cint(inputbox("enter value for c")) if((a>b)and(a>c)) then msgbox "greatest number is a="&a else if ((b>a)and(b>c)) then msgbox "greatest number is b="&b else msgbox "greatest number is c="&c end if end if
There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.
There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.
B. Since there is no black key on the piano between the white C and B keys there is no such thing as a B# or a Cb. Therefore one half step below C would be B.
that depends on what the value of c is.