28 = 4 x 7. Job done unless it's a triangle.
The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches
The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.
Length = 20 m and width = 9 m
The length of the rectangle is 27 meters and the width is 19 meters.
Any length greater than 3 inches.
This is not solvable in integers for a triangle. The solution to the nearest thousandth is: base = 9.132 and altitude = 6.132 Half base = 4.566 x alt 6.132 = 27.999, again to the nearest thousandth.
12
The area of a parallelogram is the length of the 'base' times the altitude. In a rectangle, which is a special case of parallelogram, the altitude is maximum length and also is equal in length to the other side.
Information about the base length is not enough to determine the lengths of the legs other than that they must be more than 5 units.
The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches
the length of each leg is more than 4.. the answer would be 22.5
If the base of a triangle is 12, then the other two sides can be any length at all, just as long as they add up to more than 12. If they're congruent, then each one can be anything at all more than 6.
The base length of a parallelogram is larger than its width or its side.
For the equilateral triangle in Euclidean space(i.e, the triangles you see in general) median is the same as its altitude. So, both are of equal length.
More than Mach 2 at its premium altitude.
Call the base "x", then the height would be "x+6". Now, use Pythagoras' formula to calculate the hypotenuse. Without more information, you can't know the specific length of the hypothenuse - only its relationship to the base (or to the height).
After the maximum altitude is reached the preesure is so much that the pilot cant go farther. If he goes more than the maximum altitude he will lose consiousness.