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The angle of elevation of the top of a tower from two points at a distance of 4M and 9M from the base of the tower and in the same straight line with it are complementary.Prove height of tower is 6M?
Wiki User
∙ 12y ago
Let AQ be the tower and R, S are the points 4m, 9m away from the base of the tower respectively.
The angles are complementary. Therefore, if one angle is θ, the other will be 90 − θ.
In ΔAQR,
In ΔAQS,
On multiplying equations (i) and (ii), we obtain
However, height cannot be negative.
Therefore, the height of the tower is 6 m.
Wiki User
∙ 12y ago
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