- frequency of this light : c=ln, so n=c/l (and remembering that 1 nm = 1 x10-9 m) = (3.00 x 108 m/s)/554x 10-9 m) = 5.42 x 1014 1/s - the energy of a photon of this light: E(photon) = hn = (6.6262 x 10-34 J·s)(5.42 x 1014 1/s) = 3.59 x 10-19 J
To calculate the frequency of the light, you can use the formula: frequency = speed of light / wavelength. Substituting in the values gives: frequency = 3.00 x 10^8 m/s / (554 x 10^-9 m) = 5.42 x 10^14 Hz. To calculate the energy of a photon, you can use the formula: energy = Planck's constant x frequency. Substituting in the values gives: energy = 6.63 x 10^-34 J*s x 5.42 x 10^14 Hz = 3.59 x 10^-19 J.
The heat of the flame excites the metals ions, causing them to emit visible light. The characteristic emission spectra can be used to differentiate between some elements.SO the characteristic emission spectra of Barium contains wavelengths corresponding to green color.
Barium chloride, or any other barium salt, should burn with a green flame. When a barium salt is burned, the thermal energy is transferred to the outer electrons of the barium ions. They gain enough energy to excite them to a higher energy level. They then drop back to their ground state, releasing energy. This energy corresponds to a wavelength of light, which is emitted from the ion. This wavelength corresponds to green light, hence the green flame observed.
2.5
Barium oxide is formed from barium and oxygen.
Barium Dichloride is NOT correct. The name is Barium Chloride it is a binary ionic compound.
Barium has an atomic spectra of lines, not only one line (with one wavelength); I reccomend to consult a catalog of spectral lines. See the link below.
The heat of the flame excites the metals ions, causing them to emit visible light. The characteristic emission spectra can be used to differentiate between some elements.SO the characteristic emission spectra of Barium contains wavelengths corresponding to green color.
Barium typically emits green and yellow light, so its emission lines in the visible spectrum are likely to fall within the green and yellow regions. This corresponds to wavelengths around 570-580 nm for green light and 590-610 nm for yellow light.
Barium chloride, or any other barium salt, should burn with a green flame. When a barium salt is burned, the thermal energy is transferred to the outer electrons of the barium ions. They gain enough energy to excite them to a higher energy level. They then drop back to their ground state, releasing energy. This energy corresponds to a wavelength of light, which is emitted from the ion. This wavelength corresponds to green light, hence the green flame observed.
To find the number of atoms of barium in 68.2 g of barium phosphate, you first need to calculate the moles of barium in 68.2 g of barium phosphate using the molar mass of barium phosphate. Then, you can use Avogadro's number to convert moles of barium to atoms of barium.
When barium burns, it releases energy in the form of light. The green color comes from the specific wavelength of light that is emitted as electrons transition energy levels within the barium atoms. This green light is typically associated with the presence of barium compounds in fireworks and pyrotechnic displays.
Tungsten is used in the cathode ray tube (CRT) because it has a high melting point and good thermionic emission properties, which means it can easily release electrons. The thorium oxide or barium oxide coating on the tungsten helps to improve electron emission efficiency by reducing work function and enhancing electron current. This combination allows for better electron beam production in the CRT.
2.5
First, calculate the moles of HCl in the reaction using the volume and molarity provided. Since it is a 1:1 neutralization reaction, the moles of Ba(OH)2 are equal to the moles of HCl. Next, calculate the mass of barium chloride using the molar mass provided and the moles of BaCl2 produced in the reaction.
Barium can form both barium peroxide (BaO2) and barium oxide (BaO) depending on the conditions. Barium peroxide is formed when barium reacts with oxygen in excess. Barium oxide is commonly formed when barium reacts with oxygen in limited supply or at high temperatures.
To find the molarity of the barium hydroxide solution, first calculate the number of moles of hydrochloric acid used in the titration. Then use the stoichiometry of the reaction to determine the number of moles of barium hydroxide present. Finally, divide the moles of barium hydroxide by the volume of the solution in liters to get the molarity.
"Barium: Illuminate your health with clarity and precision."