Using Pythagoras theorem its length is 40 cm and so 2(40+30) = 140 cm which is its perimeter
The diagonal is approximately 38.42 feet.
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm
Perimeter of rectangle = 2 *(l+b) =2 *(45+30)= 2 * 75 =150 cm
45
The dimensions of the rectangle are 2 units and 15 units
Assuming that the length of a rectangle is greater than its breadth, any value L such that 15 ≤ L < 30 cm will do. Then breadth, B = 30 - L cm.
The perimeter of a rectangle is not sufficient to determine its length.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
One rectangle that has a perimeter of 30 has a length of 5 and a width of 10.
The perimeter of this rectangle is 30 inches.
That depends. The perimeter of a rectangle equals the all the sides added together! The perimeter of a rectangle is the distance around it. The formula for finding the perimeter of a rectangle is: P = 2L + 2W (the length x 2 added to the width x 2). Example: A 5x10 rectangle has a perimeter of 30: (5x2 + 10x2 = 30)
The perimeter is 30 feet for this rectangle.
32.311
12+12+3+3= 30 so perimeter is 30
The diagonal is approximately 38.42 feet.
22 units
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm