Smooth Muscle tissue relaxation and contraction is responsible for dilation and constrictions of the bronchioles, respectively.
no because the diameter cam change but all the angles will stay the same.
you multiply them the change it to liters
Support structures change: irregular plates of cartilage replace the cartilage rings, and by the time the bronchioles are reached, the tube walls no longer contain supportive cartilage. Epithelium type changes: the mucosal epithelium things as it changes from pseudostratified columnar to columnar and then to cuboidal in the terminal bronchioles. Mucus-producing cells and cilia are sparse in the bronchioles. For this reason, most airborn debris found at or below the level of the bronchioles must be removed by macrophages in the alveoli. Amount of smooth muscle increases: the relative amount of smooth muscle in the tube walls increases as the passageways become smaller. A complete layer of circular smooth muscle in the bronchioles and the lack of supporting cartilage (which would hinder construction) allows the bronchioles to provide substantial resistance to air passage.
Divide the diameter by 2.
circumference/pi = diameter
The radius is half the diameter.
When you double the diameter, the circumference is also doubled.
Assuming that daimeter = diameter andraduis = radius, you simply divide diameter by 2.
Multiply the radius by 2.
The contraction and relaxation of the smooth muscle in their walls can change their diameter, thus changing the level of pressure (large diameter yields low pressure and smaller diameter yields high pressure).
Since the equation for circumference is pi*d then if you double the diameter the circumference will be doubled.
pi is the circumference divided by the diameter. it is a set universal constant and will never change = 3.1415...