x-3y+2 = 4
-3y = -x+4-2
-3y = -x+2
y = 1/3x-2/3
Slope or gradient of the perpendicular line is -3
Use y-y1 = -3(x-x1) to find the perpendicular equation
3x-4y-6 = 0
y equals -1/3x plus 4/3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
That is an impossible equation, because it is stating that m has two values.
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
[ y = 2x plus or minus any number ] is parallel to it. [ y = -0.5x plus or minus any number ] is perpendicular to it.
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
It is: minus 1.25
6
It could be y = -x+5
0909
3x-4y-6 = 0
The question is not quite clear but one equation will be y = 3x+6 and the other equation will have a slope of minus 1/3
An equation where x equals 3.
The second equation works out as y = -1/2x+6 therefore it is perpendicular
Chord equation: y = x+5 Circle equation: x^2 +4x +y^2 -18y +59 = 0 Both equations intersect at: (-1, 4) and (3, 8) which are the endpoints of the chord Midpoint of the chord: (1, 6) Slope of chord: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -(x-1) => y = -x+7
Yes that is correct