if you need to reflect a 2-d object on a graph over its parent linear function then do as follows:
(x,y) --> (-y,-x)
hope that helps
Without an equality sign the given expression can't be considered to be a straight line equation.
There isn't any. " yx-1 " is not an equation.
yx-3 is not an equation, and it has no graph.
Neither. It is a family of hyperbolae.
Without an equality sign the given expression is not an equation
Only partly true. the highest power of y also needs to be 1 - which it is.
It generates a hyperbolic paraboloid.
y=x^3
yx - 8 is an expression, not an equation nor an inequality. Consequently it cannot be graphed and so cannot have an intercept.
You can graph an equation or an inequality but you cannot graph an expression.
Yes. y + x = 4 is a linear function because the highest order (exponent) on any dependent or independent variable is 1. So if it were y^2 + x = 4 or y + x^3 = 4 or yx + 4 = 0 or anything like that, it would be non-linear. If that doesn't help, if you rearrange y + x = 4 into standard y = mx + b format you get y = -x + 4. So it's a straight line with a slope of -1 and y-intercept of 4. Any time you have an equation that just has the letters in it (x, y, z, etc. any letter) without any exponents, it's a linear equation.
well you have to look at the table if it says yx 4 then you have to use any number in the 'x"column and multiply it by the number on the "y"column then add four and check out the difference... do the same with another number and if you have the same difference then is correct.!!! :D