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if you need to reflect a 2-d object on a graph over its parent linear function then do as follows:

(x,y) --> (-y,-x)

hope that helps

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16y ago

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Related Questions

How do i graph the linear equation yx plus 5?

Without an equality sign the given expression can't be considered to be a straight line equation.


What is the slope of the equation yx-1?

There isn't any. " yx-1 " is not an equation.


What is the x-intercept of the graph of yx-3?

yx-3 is not an equation, and it has no graph.


What is the slope of the line described by the equation below yx-3?

The equation you provided, "yx - 3," is not in a standard linear form (y = mx + b), which makes it difficult to directly identify the slope. If you meant to express the equation as ( y = mx + b ), please clarify. If you intended to write ( y = x - 3 ), then the slope (m) is 1. If it's a different equation, please provide the correct format for an accurate response.


Is yx plus 4 linear or quadratic?

Neither. It is a family of hyperbolae.


What is the solution of the equation yx³-3?

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Is y x -4 a linear function Yes yx-4 is linear since the highest power on x is 1 (y x1-4)?

Only partly true. the highest power of y also needs to be 1 - which it is.


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Is y equals x plus 4 a linear function and why?

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