if you need to reflect a 2-d object on a graph over its parent linear function then do as follows:
(x,y) --> (-y,-x)
hope that helps
Without an equality sign the given expression can't be considered to be a straight line equation.
There isn't any. " yx-1 " is not an equation.
yx-3 is not an equation, and it has no graph.
The equation you provided, "yx - 3," is not in a standard linear form (y = mx + b), which makes it difficult to directly identify the slope. If you meant to express the equation as ( y = mx + b ), please clarify. If you intended to write ( y = x - 3 ), then the slope (m) is 1. If it's a different equation, please provide the correct format for an accurate response.
Neither. It is a family of hyperbolae.
Without an equality sign the given expression is not an equation
Only partly true. the highest power of y also needs to be 1 - which it is.
y=x^3
It generates a hyperbolic paraboloid.
yx - 8 is an expression, not an equation nor an inequality. Consequently it cannot be graphed and so cannot have an intercept.
Yes. y + x = 4 is a linear function because the highest order (exponent) on any dependent or independent variable is 1. So if it were y^2 + x = 4 or y + x^3 = 4 or yx + 4 = 0 or anything like that, it would be non-linear. If that doesn't help, if you rearrange y + x = 4 into standard y = mx + b format you get y = -x + 4. So it's a straight line with a slope of -1 and y-intercept of 4. Any time you have an equation that just has the letters in it (x, y, z, etc. any letter) without any exponents, it's a linear equation.
You can graph an equation or an inequality but you cannot graph an expression.