answersLogoWhite

0


Best Answer

The period of a pendulum on Mars compared to Earth would be about 1.62 times longer.

The period of a pendulum is (among other factors) inversely proportional to the square root of the acceleration due to gravity. The gravity of Mars is 0.38 that of Earth, so the square root of one over 0.38 is 1.62.

T ~= 2 pi sqrt (L/g) where theta far less than 1.

For larger theta, longer periods are incurred, with various correction factors, but the basic equation remains the same.

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: The gravitational acceleration on the surface of Mars is 3.7m s 2 What period Would a 64 meters long pendulum have on Mars?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Natural Sciences

What is the acceleration of an object thrown 3.5 meters at 44 meters per second?

On Earth it's 9.8 m/s^2. Gravitational acceleration is constant.


What is the equivalent of gravity in earth?

Gravity on the surface of Earth is equivalent to acceleration of 9.8 meters per second2 .


What percent of earth's gravity does mars have?

The acceleration of an object under the force of gravity alone is*: a = GM/R^2 a = acceleration G = gravitational constant (G = 6.674E-13 Nm^2/kg^2) M = mass of the object/planet R = distance from the center of the object/planet At the equator, an object dropped near the surface of Earth falls with an acceleration of 9.78 meters per square second. At the equator on Mars, and object dropped at the surface will fall with an acceleration of 3.71 meters per square second. Therefore Mars has about 38% of the Earth's gravity. *This equation is only true for spherically-distributed masses


How is weight related to gravitational force?

Weight = Mass * Acceleration of gravity. Weight = force of gravity on particular object. Weight = force of gravity on an object; Gravity = attracts all objects toward each other


What does the phrase ten meters per second squared describes?

Ten meters per second squared, or ten meters per second per second is the term used for acceleration. In this case it is referring to the acceleration caused by gravity. If you were on the top of a steep cliff and threw a ball over the side, it would accelerate at 10 meters per second squared. So after 10 meters is would be going 20 meters a second.

Related questions

What is the planet earth's gravitational force?

This can be measured by the acceleration due to gravity at the surface. Earth's surface gravitational acceleration is about 9.8 m/s2


What is Uranus gravitational field strength meterS per second?

Gravitational acceleration is not measured in meters/second, but in meters/second2. Uranus' surface gravity is about 8.69 meters/second2, a little less than that of Earth.


What is the Gravitational Acceleration of Earth?

On or near the surface of the Earth, the acceleration of gravity is9.8 meters (32.2 feet) per second2 .It becomes less as you move away from the surface.(Either up or down!)


What is the gravity on eath?

Gravitational acceleration near Earth's surface is about 9.8 meters/second2. Equivalently, every kilogram - near Earth's surface - has a weight of about 9.8 newton.


What is Venus's gravitational pull in meters per second squared?

The acceleration of gravity on or near the surface of Venus is 8.87 m/s2 . . .about 91% of its value on or near the surface of Earth.


What is the gravitational potential energy of an object equal to?

It is the product of the mass of the object in Kg, the gravitational acceleration which is 9.81 m/sec2, and the height of the object above earth's surface in meters. Result is in Joules


What is the value for gravitational acceleration to two decimal places in meters per second squared?

It is 9.81 ms-2, although there are variations across the surface of the earth.


What is the acceleration of an object thrown 3.5 meters at 44 meters per second?

On Earth it's 9.8 m/s^2. Gravitational acceleration is constant.


What is the length of a pendulum of period 1.6 seconds?

use simple pendulum formula T=2pie/square root L over g(where L is the length of pendulum,T is time period,and g is gravitational acceleration normally taken as 9.81) .then square both sides to get rid of square root.answer is 1.998476789 meters which is 2.0 to two significant figures.


What is the acceleration of gravity in meters?

"Meters" is not a unit of acceleration.The acceleration of gravity on or near the surface of the Earth is about9.8 meters/second2 .It's different in other places.


What is the magnitude of the acceleration of an object free falling for 3 meters in the first second on a planet with no atmosphere?

The magnitude of acceleration depends on the gravitational pull from the planet. The amount of gravitational pull depends on the size and mass of the planet. On Earth gravity will produce an acceleration of 9.8 meters per second squared if there was no atmosphere.


A simple pendulum with a length of 80 cm oscillates on the Earth s surface What is the frequency of oscillations?

The formula for the period of oscillation (for the case of small oscillations) is:T = 2 x pi x root(L / g) Just replace L by the length (you must convert it to meters first), and g by the gravitational acceleration, which is approximately 9.8 (in SI units).