The period of a pendulum on Mars compared to Earth would be about 1.62 times longer.
The period of a pendulum is (among other factors) inversely proportional to the square root of the acceleration due to gravity. The gravity of Mars is 0.38 that of Earth, so the square root of one over 0.38 is 1.62.
T ~= 2 pi sqrt (L/g) where theta far less than 1.
For larger theta, longer periods are incurred, with various correction factors, but the basic equation remains the same.
On Earth it's 9.8 m/s^2. Gravitational acceleration is constant.
Gravity on the surface of Earth is equivalent to acceleration of 9.8 meters per second2 .
The acceleration of an object under the force of gravity alone is*: a = GM/R^2 a = acceleration G = gravitational constant (G = 6.674E-13 Nm^2/kg^2) M = mass of the object/planet R = distance from the center of the object/planet At the equator, an object dropped near the surface of Earth falls with an acceleration of 9.78 meters per square second. At the equator on Mars, and object dropped at the surface will fall with an acceleration of 3.71 meters per square second. Therefore Mars has about 38% of the Earth's gravity. *This equation is only true for spherically-distributed masses
Weight = Mass * Acceleration of gravity. Weight = force of gravity on particular object. Weight = force of gravity on an object; Gravity = attracts all objects toward each other
Ten meters per second squared, or ten meters per second per second is the term used for acceleration. In this case it is referring to the acceleration caused by gravity. If you were on the top of a steep cliff and threw a ball over the side, it would accelerate at 10 meters per second squared. So after 10 meters is would be going 20 meters a second.
This can be measured by the acceleration due to gravity at the surface. Earth's surface gravitational acceleration is about 9.8 m/s2
Gravitational acceleration is not measured in meters/second, but in meters/second2. Uranus' surface gravity is about 8.69 meters/second2, a little less than that of Earth.
On or near the surface of the Earth, the acceleration of gravity is9.8 meters (32.2 feet) per second2 .It becomes less as you move away from the surface.(Either up or down!)
Gravitational acceleration near Earth's surface is about 9.8 meters/second2. Equivalently, every kilogram - near Earth's surface - has a weight of about 9.8 newton.
The acceleration of gravity on or near the surface of Venus is 8.87 m/s2 . . .about 91% of its value on or near the surface of Earth.
It is the product of the mass of the object in Kg, the gravitational acceleration which is 9.81 m/sec2, and the height of the object above earth's surface in meters. Result is in Joules
It is 9.81 ms-2, although there are variations across the surface of the earth.
On Earth it's 9.8 m/s^2. Gravitational acceleration is constant.
use simple pendulum formula T=2pie/square root L over g(where L is the length of pendulum,T is time period,and g is gravitational acceleration normally taken as 9.81) .then square both sides to get rid of square root.answer is 1.998476789 meters which is 2.0 to two significant figures.
"Meters" is not a unit of acceleration.The acceleration of gravity on or near the surface of the Earth is about9.8 meters/second2 .It's different in other places.
The magnitude of acceleration depends on the gravitational pull from the planet. The amount of gravitational pull depends on the size and mass of the planet. On Earth gravity will produce an acceleration of 9.8 meters per second squared if there was no atmosphere.
The formula for the period of oscillation (for the case of small oscillations) is:T = 2 x pi x root(L / g) Just replace L by the length (you must convert it to meters first), and g by the gravitational acceleration, which is approximately 9.8 (in SI units).