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The half life of iron 59 is 44.5 days how much of 2mg sample will remain after 133.5 days?
Wiki User
∙ 14y ago
If the half-life of a nuclide is 44.5 days, then 178 days is four half-lives. After four half-lives, 0.0625 (0.54) of the original nuclide remains. If 50g is the original mass, then the mass after 4 half-lives is 3.125g.
AT = A0 2(-T/H)
A178 = (50) 2(-44.5/178)
A178 = 3.125
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoAfter three half-lives (133.5 / 44.5) one eighth (0.125) of an isotope will remain, so the 2mg sample of 59Fe will have decayed to 0.5mg.
AT = A0 2(-T/H)
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