Using atomic weights for Na = 23 and N=14 and O = 16, one arrives at a mass for 1 mole of NaNO3 of
23 + 14 + (3x16) = 85 grams/mole
The molar mass of sodium nitrate is 84,9947 g.
84.9947 g/mol
What is the mass of 1.72 moles of sodium nitrate? Use the Periodic Table and the polyatomic ion resource.
The molar mass of NaNO3 is 84.9947 g/mol. Multiplying by 0.254 mol gives 21.5886538 g, or correctly sigFig'd, 21.6 g
= 0.75 mol x 32 g.mol-1 = 24 g
1 mol = 197g therefore, 32 mol = 6306 grams
Carbon monoxide, CO, has one atom of carbon and one atom of oxygen. The molar mass of carbon is 12.0107 g mol-1 and the molar mass of oxygen is 15.9994 g mol-1, so the molar mass of CO is 28.0101 g mol-1.
This is equal to the molar mass of this substance.
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
I'm assuming that your instructor is using the terms mass and weight interchangeably. First determine the molar mass of each compound by multiplying the molar mass of each element by its subscript and add them together. The molar mass of an element is its atomic weight on the periodic table in grams. Molar mass of sodium nitrate (NaNO3) (1 atom Na x 22.98970g/mol Na) + (1 atom N x 14.0067g/mol N) + (3 atoms O x 15.9994g/mol O) = 84.9946g/mol NaNO3 Molar mass of carbon dioxide (CO2) (1 atom C x 12.0107g/mol C) + (2 atoms O x 15.9994g/mol O) = 44.0095g/mol CO2 Now multiply the molar mass for each compound by the number given and compare the results to determine which has the greater mass. 5mol NaNO3 x 84.9946g/mol NaNO3 = 424.973g NaNO3 4 mol CO2 x 44.0095g/mol CO2 = 176.038 So 5 moles of sodium nitrate has a mass greater than 4 moles of carbon dioxide.
The molar mass of NaNO3 is 84.9947 g/mol. Multiplying by 0.254 mol gives 21.5886538 g, or correctly sigFig'd, 21.6 g
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
According to the periodic table, the atomic mass of rubidium, Rb is 85.5. This is numerically equal to the molar mass in g/mol. Therefore the mass of 1 mol of Rb is 85.5g.Mass of 1 mol means the molar mass of the element. Molar mass of Rubidium is 85.47 gmol-1. Rb is in the 1st group.
#moles = mass/molar mass mass = #moles*molar mass mass = .10 moles*(atomic weight of na+atomic weight of N+3(atomic weight of oxygen)
0.94 mol
65.38(4) g mol-1
Mass (g) = Number of moles (mol) x Molar mass (g/mol) Here are the calculations for each sample: 7 moles of aluminum (Al): The molar mass of Al is approximately 26.98 g/mol. Mass = 7 mol x 26.98 g/mol = 188.86 g 1.400e-15 teramoles (Tmol) of carbon dioxide (CO2): The molar mass of CO2 is approximately 44.01 g/mol. Mass = 1.400e-15 mol x 44.01 g/mol = 6.16e-14 g 7.7e12 picomoles (pmol) of sodium nitrate (NaNO3): The molar mass of NaNO3 is approximately 85 g/mol. Mass = 7.7e12 mol x 85 g/mol = 6.59e-10 g 2.73e-4 kilomoles (kmol) of C2H6O: The molar mass of C2H6O (ethanol) is approximately 46.07 g/mol. Mass = 2.73e-4 mol x 46.07 g/mol = 0.1256 g 1.02e-9 megamoles (Mmol) of uranium (U): The molar mass of uranium is approximately 238.03 g/mol. Mass = 1.02e-9 mol x 238.03 g/mol = 2.43e-7 g 4.01 millimoles (mmol) of hydrobromic acid (HBr): The molar mass of HBr is approximately 80.91 g/mol. Mass = 4.01e-3 mol x 80.91 g/mol = 0.3247 g So, the mass of each sample is as follows: 188.86 grams of aluminum 6.16e-14 grams of carbon dioxide 6.59e-10 grams of sodium nitrate 0.1256 grams of C2H6O 2.43e-7 grams of uranium 0.3247 grams of hydrobromic acid.
Mole / Molar mass = mass = 0.118 [mol] /169.87 [g mol−1] = 20.05 grams
Balanced Equation. NaOH + HNO3 >> NaNO3 + H2O Now, Molarity = moles of solute/liters of solution 0.800M HNO3 + mol/2.50L mol of HNO3 = 2 2mol HNO3 (1mol NaOH/1molHNO3 )(39.998g NaOH/1mol NaOH ) = 79.996 grams
= 0.75 mol x 32 g.mol-1 = 24 g